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Using Letter-

🎓 Class 7📖 Ganita Prakash📖 8 notes🧠 15 Q&A⏱️ ~12 min

Using Letter-Study Notes

NCERT-aligned · 8 notes · 3 shown free

Introduction

Explanation

Introduction

This chapter 'Using Letters' introduces the fundamental concept of algebra, which is a branch of mathematics that uses letters and symbols to represent numbers and quantities in formulas and equations. The use of letters allows us to generalize arithmetic operations and express mathematical relationships in a concise and flexible way. The chapter begins by explaining the need for letters in mathematics, especially when dealing with unknown quantities or when expressing general rules applicable to many numbers. Letters such as x, y, a, b, etc., are used to denote variables, constants, or unknowns. This approach helps in forming expressions and equations that can be solved or simplified. The chapter emphasizes that letters are not just arbitrary symbols but represent numbers whose values can vary or be unknown. This abstraction is crucial for solving problems where the exact numbers are not known initially. The section also introduces the concept of algebraic expressions, which are combinations of numbers, letters, and operations like addition, subtraction, multiplication, and division. Through the use of letters, we can write expressions like 3x + 5 or 2a - b, which represent numerical values depending on the values of the letters. The chapter highlights the importance of learning to use letters correctly, including understanding terms, coefficients, constants, and the rules for writing algebraic expressions. This foundation is essential for progressing to more advanced topics in algebra and mathematics in general.

  • Letters represent numbers in algebra to generalize arithmetic operations.
  • Variables are letters that can take different numerical values.
  • Algebraic expressions combine numbers, letters, and operations.
  • Using letters helps express general mathematical rules and relationships.
  • Understanding terms, coefficients, and constants is key to algebra.
  • Algebra forms the basis for solving equations with unknowns.
  • 📌 Algebra: A branch of mathematics using letters to represent numbers.
  • 📌 Variable: A letter representing a number that can change or is unknown.
  • 📌 Algebraic expression: A combination of numbers, letters, and operations.

What is a Variable?

Concept

What is a Variable?

In this section, the concept of a variable is explained in detail. A variable is a letter used to represent a number whose value can change or is not yet known. Variables allow us to write general expressions and equations that apply to many situations rather than just one specific case. The section explains that variables are usually denoted by letters such as x, y, z, a, b, c, etc. The value of a variable can vary depending on the problem or context. For example, if x represents the number of pencils in a box, then x could be 10, 20, or any other number depending on the box. The section also distinguishes variables from constants, which are fixed numbers. It explains that variables are essential for expressing mathematical relationships and for solving problems where the exact numbers are unknown. Using variables, we can write expressions like 2x + 3, which means two times a number plus three. The section further explains that variables can be used in equations to find unknown values by solving for the variable. This is the foundation of algebraic problem-solving. The section encourages students to understand that variables are placeholders for numbers and that their values can be determined through calculations or given conditions.

  • A variable is a letter representing an unknown or changeable number.
  • Variables allow generalization of mathematical expressions and equations.
  • Common variable letters include x, y, z, a, b, c.
  • Variables differ from constants, which have fixed values.
  • Variables help in forming expressions like 2x + 3.
  • Solving equations involves finding the value of variables.
  • 📌 Variable: A symbol representing a number that can vary or is unknown.
  • 📌 Constant: A fixed number that does not change.

What is an Expression?

Definition

What is an Expression?

This section defines an algebraic expression as a combination of numbers, variables, and arithmetic operations such as addition, subtraction, multiplication, and division. Expressions do not contain an equality sign (=); if they do, they become equat

Practice QuestionsUsing Letter-

Includes NCERT exercise questions with answers

Q1.(a) If t = 4 , what is the time taken to travel from Yahapur to Vahapur? (b) What is the algebraic expression for the time taken to travel from Yahapur to Vahapur? [Hint: Draw a rough diagram to visualise the situation]

Answer:

(a) When t = 4, the time taken to travel from Yahapur to Vahapur is 22 minutes. (b) The algebraic expression for the time taken to travel from Yahapur to Vahapur is 4t + 6 minutes.

Explanation:

The train travels between stations with equal time t for each segment and stops for 2 minutes at each of the three stations. Total travel time = 4t + 6 minutes (4 segments of travel plus 3 stops of 2 minutes each). For t=4, time = 4*4 + 6 = 22 minutes.

EasyNCERT
Q2.Simplify the following expressions: (a) 3a + 9b - 6 + 8a - 4b - 7a + 16 (b) 3(3a - 3b) - 8a - 4b - 16 (c) 2(2x - 3) + 8x + 12 (d) 8x - (2x - 3) + 12 (e) 8h - (5 + 7h) + 9 (f) 23 + 4(6m - 3n) - 8n - 3m - 18

Answer:

(a) 3a + 9b - 6 + 8a - 4b - 7a + 16 = 4a + 5b + 10 (b) 3(3a - 3b) - 8a - 4b - 16 = a - 13b - 16 (c) 2(2x - 3) + 8x + 12 = 12x + 6 (d) 8x - (2x - 3) + 12 = 6x + 15 (e) 8h - (5 + 7h) + 9 = h + 4 (f) 23 + 4(6m - 3n) - 8n - 3m - 18 = 5 + 21m - 20n

Explanation:

Simplify each expression by removing parentheses, combining like terms and constants: (a) 3a + 9b - 6 + 8a - 4b - 7a + 16 = (3a + 8a - 7a) + (9b - 4b) + (-6 + 16) = 4a + 5b + 10 (b) 3(3a - 3b) - 8a - 4b - 16 = 9a - 9b - 8a - 4b - 16 = a - 13b - 16 (c) 2(2x - 3) + 8x + 12 = 4x - 6 + 8x + 12 = 12x + 6 (d) 8x - (2x - 3) + 12 = 8x - 2x + 3 + 12 = 6x + 15 (e) 8h - (5 + 7h) + 9 = 8h - 5 - 7h + 9 = h + 4 (f) 23 + 4(6m - 3n) - 8n - 3m - 18 = 23 + 24m - 12n - 8n - 3m - 18 = 5 + 21m - 20n

EasyNCERT
Q3.Add the expressions given below: (a) 4d - 7c + 9 and 8c - 11 + 9d (b) -6f + 19 - 8s and -23 + 13f + 12s (c) 8d - 14c + 9 and 16c - (11 + 9d) (d) 6f - 20 + 8s and 23 - 13f - 12s (e) 13m - 12n and 12n - 13m (f) -26m + 24n and 26m - 24n

Answer:

(a) (4d - 7c + 9) + (8c - 11 + 9d) = 13d + c - 2 (b) (-6f + 19 - 8s) + (-23 + 13f + 12s) = 7f + 4s - 4 (c) (8d - 14c + 9) + (16c - 11 - 9d) = 2c - d - 2 (d) (6f - 20 + 8s) + (23 - 13f - 12s) = -7f - 4s + 3 (e) (13m - 12n) + (12n - 13m) = 0 (f) (-26m + 24n) + (26m - 24n) = 0

Explanation:

Add the corresponding terms: (a) 4d + 9d = 13d; -7c + 8c = c; 9 - 11 = -2 (b) -6f + 13f = 7f; 19 - 23 = -4; -8s + 12s = 4s (c) 8d - 9d = -d; -14c + 16c = 2c; 9 - 11 = -2 (d) 6f - 13f = -7f; -20 + 23 = 3; 8s - 12s = -4s (e) 13m - 13m = 0; -12n + 12n = 0 (f) -26m + 26m = 0; 24n - 24n = 0

EasyNCERT
Q4.Subtract the expressions given below: (a) 9a - 6b + 14 from 6a + 9b - 18 (b) -15x + 13 - 9y from 7y - 10 + 3x (c) 17g + 9 - 7h from 11 - 10g + 3h (d) 9a - 6b + 14 from 6a - (9b + 18) (e) 10x + 2 + 10y from -3y + 8 - 3x (f) 8g + 4h - 10 from 7h - 8g + 20

Answer:

(a) (6a + 9b - 18) - (9a - 6b + 14) = -3a + 15b - 32 (b) (7y - 10 + 3x) - (-15x + 13 - 9y) = 16y + 18x - 23 (c) (11 - 10g + 3h) - (17g + 9 - 7h) = 10h - 27g + 2 (d) (6a - (9b + 18)) - (9a - 6b + 14) = -(3a + 3b + 32) (e) (-3y + 8 - 3x) - (10x + 2 + 10y) = -13y - 13x + 6 (f) (7h - 8g + 20) - (8g + 4h - 10) = 3h - 16g + 30

Explanation:

Subtract the second expression from the first by changing signs and combining like terms: (a) 6a - 9a = -3a; 9b + 6b = 15b; -18 - 14 = -32 (b) 7y + 9y = 16y; -10 - 13 = -23; 3x + 15x = 18x (c) 11 - 9 = 2; -10g - 17g = -27g; 3h + 7h = 10h (d) 6a - 9b - 18 - 9a + 6b - 14 = -3a + (-3b) - 32 = -(3a + 3b + 32) (e) -3y - 10y = -13y; 8 - 2 = 6; -3x - 10x = -13x (f) 7h - 8g + 20 - 8g - 4h + 10 = 3h - 16g + 30

MediumNCERT
Q5.Describe situations corresponding to the following algebraic expressions: (a) 8x + 3y (b) 15x - 2x

Answer:

(a) Situation: A fruit seller sells mangoes at ₹8 each and bananas at ₹3 each. If a customer buys x mangoes and y bananas, the total cost would be 8x + 3y. (b) Situation: A shopkeeper has 15 pencils in a packet. The cost of one pencil is ₹x. Two pencils in the packet are not sold. Find the amount received for this packet, which is 15x - 2x.

Explanation:

These expressions represent real-life situations: (a) Total cost for x mangoes and y bananas at given prices. (b) Total cost for 15 pencils minus the cost of 2 pencils not sold.

EasyNCERT
Q6.Imagine a straight rope. If it is cut once as shown in the picture, we get 2 pieces. If the rope is folded once and then cut as shown, we get 3 pieces. Observe the pattern and find the number of pieces if the rope is folded 10 times and cut. What is the expression for the number of pieces when the rope is folded r times and cut?

Answer:

If the rope is folded 10 times and cut, we get 10 + 2 = 12 pieces. In general, when the rope is folded r times and cut, the number of pieces obtained is r + 2.

Explanation:

Each fold adds one more piece when cut. Starting with 1 cut giving 2 pieces, folding r times gives r + 2 pieces.

EasyNCERT
Q7.Look at the matchstick pattern below. Observe and identify the pattern. How many matchsticks are required to make 10 such squares? How many are required to make w squares?

Answer:

To make 10 squares, we need 4 + 3 × 9 = 31 matchsticks. To make w squares, the number of matchsticks required is 4 + 3(w - 1).

Explanation:

The first square requires 4 matchsticks. Each additional square shares a side, so only 3 extra matchsticks are needed per square after the first. Hence total = 4 + 3(w - 1).

MediumNCERT
Q8.Have you noticed how the colours change in a traffic signal? The sequence of colour changes is shown below. Find the colour at positions 90, 190, and 343. Write expressions to describe the positions for each colour.

Answer:

Position 90: Colour is Yellow. Position 190: Colour is Yellow. Position 343: Colour is Green. Expressions: Red light occurs at positions 4n - 3, Green light at positions 4n - 1, Yellow light at positions 2n, where n is a positive integer.

Explanation:

The traffic light sequence repeats every 4 positions. By dividing the position number by 4 and analyzing the remainder, we determine the colour: - Positions 4n - 3: Red - Positions 4n - 1: Green - Positions 2n: Yellow

MediumNCERT