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MathematicsClass 7Finding The

Finding The | Class 7 Mathematics Notes

By ConceptScroll Team · Published on 17 July 2026 · 3 min read

Finding The – this guide gives you a concise, exam-ready overview of Finding The from Class 7 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.

Solving Equations

This section focuses on the step-by-step process of solving simple linear equations in one variable. The chapter explains that the goal is to find the value of the variable that makes the equation true. Using the properties of equality, students learn to isolate the variable on one side of the equation. The process involves performing inverse operations to undo addition, subtraction, multiplication, or division. For example, if the equation is x + 4 = 9, subtract 4 from both sides to get x = 5. The chapter emphasizes checking the solution by substituting the value back into the original equation. The section also introduces equations where the variable appears on both sides, such as 2x + 3 = x + 7. Here, students learn to bring variables to one side and constants to the other before solving. The chapter provides multiple examples with detailed solutions to build confidence. It also discusses cases where equations have no solution or infinite solutions, explaining the concepts clearly with examples.

📊 Diagram: No specific diagrams; stepwise solution process illustrated through worked examples.

🧪 Activity: No specific activity in this section.

🔗 Connection: Prepares students for solving word problems using equations in the next section.

Frequently asked questions

We have the expression 3k + 1 which gives the number of tiles needed to make an arrangement in Step k. To check whether an arrangement is possible using 100 tiles at some Step k, we can solve the equation: 3k + 1 = 100. Find the value of k.

Given the equation 3k + 1 = 100, Subtract 1 from both sides: 3k = 100 - 1 3k = 99 Divide both sides by 3: k = 99 ÷ 3 k = 33 Therefore, the arrangement using 100 tiles corresponds to Step 33.

Madhubanti wants to organise a party. She decides to buy snacks for the party from the chaat shop in town. Each plate of snacks costs ₹25. The shop charges an additional fixed amount of ₹50 to deliver the snacks to Madhubanti’s house. There are 5 members in Madhubanti’s family, including herself. Her parents tell her she can spend ₹500 on this party. How many friends can she invite to the party if she wants to give a plate of snacks to each person, including her family and friends?

Total money available = ₹500 Delivery charge = ₹50 Money left for snacks = 500 - 50 = ₹450 Cost per plate = ₹25 Number of plates that can be bought = 450 ÷ 25 = 18 Number of family members = 5 Number of friends invited = 18 - 5 = 13 Therefore, Madhubanti can invite 13 friends.

Two friends want to save money. Jahnavi starts with an initial amount of ₹4000, and in addition, saves ₹650 per month. Sunita starts with ₹5050 and saves ₹500 per month. After how many months will they have the same amount of money?

Let m be the number of months after which their savings are equal. Jahnavi's savings after m months = 4000 + 650m Sunita's savings after m months = 5050 + 500m Set equal: 4000 + 650m = 5050 + 500m Subtract 500m from both sides: 4000 + 150m = 5050 Subtract 4000 from both sides: 150m = 1050 Divide both sides by 150: m = 1050 ÷ 150 = 7 Therefore, after 7 months, both will have the same amount of money.

Solve 28 (x + 4) + 300 = 1000.

Given equation: 28(x + 4) + 300 = 1000 Step 1: Subtract 300 from both sides: 28(x + 4) = 1000 - 300 28(x + 4) = 700 Step 2: Divide both sides by 28: x + 4 = 700 ÷ 28 x + 4 = 25 Step 3: Subtract 4 from both sides: x = 25 - 4 x = 21 Therefore, the solution is x = 21.

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