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Thermodynamics

🎓 Class 11📖 Physics Part-II📖 9 notes🧠 15 Q&A⏱️ ~14 min

ThermodynamicsStudy Notes

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12.1 Introduction

Explanation

12.1 Introduction

The chapter on Kinetic Theory begins by tracing the historical development of the understanding of gases. Boyle discovered Boyle's law in 1661, which relates pressure and volume of gases. Early scientists such as Boyle and Newton speculated that gases are composed of tiny atomic particles. However, the formal atomic theory was established much later, more than 150 years after these initial ideas. The kinetic theory explains the behavior of gases based on the concept that gases consist of rapidly moving atoms or molecules. This theory is applicable because inter-atomic forces, which are significant in solids and liquids, are negligible in gases due to their large intermolecular distances. The kinetic theory was developed in the nineteenth century by scientists like Maxwell and Boltzmann and has been remarkably successful in explaining various gas properties. It provides a molecular interpretation of pressure and temperature, is consistent with gas laws and Avogadro's hypothesis, and correctly explains specific heat capacities of many gases. Additionally, it relates measurable macroscopic properties such as viscosity, thermal conduction, and diffusion to molecular parameters, allowing estimates of molecular sizes and masses. This chapter introduces these fundamental concepts of kinetic theory.

  • Boyle's law discovered in 1661 relates pressure and volume of gases.
  • Early atomic ideas by Boyle and Newton preceded formal atomic theory.
  • Kinetic theory models gases as rapidly moving atoms/molecules.
  • Inter-atomic forces are negligible in gases, unlike solids/liquids.
  • Developed by Maxwell, Boltzmann in the 19th century.
  • Explains pressure, temperature, specific heats, and molecular properties.
  • 📌 Kinetic theory: Explains gas behavior via molecular motion.
  • 📌 Atomic theory: Matter composed of atoms.
  • 📌 Inter-atomic forces: Forces between atoms, negligible in gases.

12.2 Molecular nature of matter

Explanation

12.2 Molecular nature of matter

This section elaborates on the atomic hypothesis, emphasizing its fundamental importance as highlighted by physicist Richard Feynman. Feynman considered the discovery that matter is made up of atoms as one of the most significant scientific findings. He suggested that even if humanity were to lose all scientific knowledge, the atomic hypothesis should be passed on to future generations or other creatures in the universe. The atomic hypothesis states that all things are made of atoms—tiny particles in perpetual motion, attracting each other when slightly apart but repelling when squeezed together. The idea that matter is not continuous but composed of indivisible particles was speculated in many ancient cultures. In ancient India, the Vaiseshika school founded by Kanada (6th century B.C.) developed an atomic picture where atoms (paramanu) were eternal, indivisible, and ultimate parts of matter. They postulated four kinds of atoms corresponding to earth, water, fire, and air, each with characteristic mass and properties. Atoms combine to form molecules (dvyanuka for two atoms, tryanuka for three atoms), and their properties depend on the nature and ratio of constituent atoms. The size of atoms was estimated in ancient texts like Lalitavistara, close to modern estimates (~10^-10 m). In ancient Greece, Democritus proposed that atoms differ in shape and size, explaining different material properties. John Dalton later formalized atomic theory to explain chemical laws such as definite and multiple proportions. Dalton's theory, combined with Avogadro's hypothesis (equal volumes of gases at same temperature and pressure contain equal numbers of molecules), forms the molecular theory of matter. Modern observations confirm that molecules, made of atoms, constitute matter. Electron and scanning tunneling microscopes allow visualization of atoms. Typical atomic sizes are about 1 angstrom (10^-10 m), with interatomic distances in solids and liquids around 2 angstroms, and much larger in gases. The mean free path in gases—the average distance a molecule travels between collisions—is much larger, explaining gaseous behavior. Atomic theory has evolved further to reveal subatomic structure (nucleus, protons, neutrons, quarks), but for kinetic theory, the focus remains on molecules in incessant motion.

  • Richard Feynman emphasized the atomic hypothesis as fundamental.
  • Ancient Indian Vaiseshika school postulated eternal, indivisible atoms.
  • Four kinds of atoms: earth, water, fire, air with characteristic properties.
  • Atoms combine to form molecules; size estimates close to modern values.
  • Democritus in Greece proposed atoms differ in shape and size.
  • Dalton formalized atomic theory explaining chemical laws.
  • Avogadro's hypothesis relates gas volumes to molecule numbers.
  • Modern instruments visualize atoms; atomic size ~10^-10 m.
  • Interatomic distances: solids/liquids ~2 Å; gases much larger.
  • Mean free path in gases is large, enabling gaseous behavior.
  • Atomic theory extended to subatomic particles but focus here is molecular.

12.3 Behaviour of gases

Explanation

12.3 Behaviour of gases

This section discusses the macroscopic behavior of gases and their relation to molecular properties. Gases are easier to understand than solids and liquids because their molecules are far apart, making intermolecular interactions negligible except du

Practice QuestionsThermodynamics

Includes NCERT exercise questions with answers

Q1.What would be the most likely value for C T , the molar heat capacity at constant temperature?
A.0
B.0 < C T < C v
C.C v < C T < C p
D.C T =infinity

Answer:

0

Explanation:

[{"id": "df61cdd7-ddab-c6cb-2736-edc612f0e5f2", "type": "html", "value": " Molar heat capacity at constant temperature ( C T ) is defined as the amount of heat required to raise the temperature of 1 g of gas through 1° C keeping its temperature constant. But it is impossible to rise the temperature of 1 g of gas through 1°C keeping its temperature constant. So the two statements contradict to each other. Thus the most likely value for molar heat capacity at constant temperature ( C T ) will be zero. "}]

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Q2.In a cylinder, infinitesimal amount of work done by the gas on piston is given by
A.F×dl
B.P×A×dl
C.P×dV
D.all of the above mentioned

Answer:

P×dV

Explanation:

[{"id": "e7864369-125a-afb1-bb6a-dd7c31e9b5d5", "type": "html", "value": " F=P×A and work equals force multiplied by displacement. Hence F×S = P×A×S = PdV "}]

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Q3.What will be the required minimum area for the transfer of heat. A large heat exchanger transfers a total of 200 MW. Assume the wall separating steam and sea water is 8 mm of steel, conductivity 16 W/m K and that a maximum of 5°C difference between the two fluids is allowed. Find the required minimum area for the heat transfer.
A.47×10 3 m 2
B.28×10 3 m 2
C.64×10 3 m 2
D.20×10 3 m 2

Answer:

20×10 3 m 2

Explanation:

[{"id": "4add7f45-a8ae-9243-a02f-0d408f7bbb93", "type": "html", "value": " Steady conduction Q = 200 × 10 6 W, ∆x = 0.008m Q = k A ∆T/∆x Α = Q ∆x / k∆Τ A = 200 × 10 6 × 0.008 / (16 × 5) = 20×10 3 m 2 . "}]

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Q4.What will be the final volume of air? A piston cylinder contains air at 900 kPa, 290 K and a volume of 0.03m 3 if constant pressure process gives 54 kJ of work out.
A.0.18 m 3
B.0.21 m 3
C.0.09 m 3
D.0.05 m 3

Answer:

0.09 m 3

Explanation:

[{"id": "1812a42c-e348-3288-00fa-4be83655ae6f", "type": "html", "value": " W = ∫ P dV = PΔV ΔV = W/P = 54/900 = 0.06 m 3 V 2 = V 1 + ΔV = 0.03 + 0.06 = 0.09 m 3 "}]

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Q5.For which of the following process is the entropy change zero? since ΔS > 0 for all process.
A.Isobaric
B.Isothermal
C.Adiabatic
D.None of these

Answer:

Adiabatic

Explanation:

[{"id": "daee7bbf-8618-900c-d5dd-8be8f40bd660", "type": "html", "value": " Entropy change (Δ S ) for a reversible process is defined as, Δ S = Δ Q / T Where, Δ Q is the change in heat energy that is transferred into or out of the closed system at constant temperature T . From equation Δ S = Δ Q / T , the entropy change will be zero when Δ Q / T = 0 If the above condition is satisfied, Δ Q =0 as T is constant. This shows that the change in the entropy is constant. So, the process will be adiabatic process as the amount of heat remains constant. Thus in an adiabatic process the entropy change will be zero. "}]

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Q6.When does a real gas obey the ideal gas equation closely?
A.At high pressure and low temperature
B.At low pressure and high temperature
C.At low pressure and temperature
D.At high pressure and temperature

Answer:

At low pressure and high temperature

Explanation:

[{"id": "932b0458-1d35-72eb-193c-d7870f4ed9be", "type": "html", "value": " At low pressure and high temperature, the intermolecular attraction and the volume of the molecules compared to the total volume of the gas are not of much significance. "}]

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Q7.(a) When a molecule (or an elastic ball) hits a (massive) wall, it rebounds with the same speed. When a ball hits a massive bat held firmly, the same thing happens. However, when the bat is moving towards the ball, the ball rebounds with a different speed. Does the ball move faster or slower? (Ch.5 will refresh your memory on elastic collisions.) (b) When gas in a cylinder is compressed by pushing in a piston, its temperature rises. Guess at an explanation of this in terms of kinetic theory using (a) above. (c) What happens when a compressed gas pushes a piston out and expands. What would you observe? (d) Sachin Tendulkar used a heavy cricket bat while playing. Did it help him in anyway?

Answer:

(a) Let the speed of the ball be u relative to the wicket behind the bat. If the bat is moving towards the ball with a speed V relative to the wicket, then the relative speed of the ball to bat is V + u towards the bat. When the ball rebounds (after hitting the massive bat) its speed, relative to bat, is V + u moving away from the bat. So relative to the wicket the speed of the rebounding ball is V + (V + u) = 2V + u, moving away from the wicket. So the ball speeds up after the collision with the bat. The rebound speed will be less than u if the bat is not massive. For a molecule this would imply an increase in temperature. (b) When gas in a cylinder is compressed by pushing in a piston, the piston moves towards the gas molecules like the bat moving towards the ball. The molecules rebound with increased speed, which means their average kinetic energy increases, leading to a rise in temperature. (c) When a compressed gas pushes a piston out and expands, the piston moves away from the gas molecules like the bat moving away from the ball. The molecules lose some kinetic energy in collisions with the piston, so the temperature of the gas decreases. (d) Using a heavy cricket bat helps because the bat can be considered massive compared to the ball, so when the ball hits the bat, it rebounds with increased speed, allowing the player to hit the ball harder and farther.

Explanation:

The explanation is based on elastic collisions and relative motion. When the bat moves towards the ball, the relative speed of approach increases, so the rebound speed relative to the ground increases, resulting in the ball moving faster. This analogy applies to gas molecules colliding with moving piston walls, explaining temperature changes during compression and expansion.

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Q8.Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be 3 Å.

Answer:

Given: Diameter of oxygen molecule, d = 3 Å = 3 × 10⁻¹⁰ m STP conditions: 1 mole of gas occupies 22.4 litres = 22.4 × 10⁻³ m³ Step 1: Calculate volume of one oxygen molecule assuming spherical shape: Volume of one molecule, v_m = (4/3)π (r)^3 = (4/3)π (d/2)^3 = (4/3)π (1.5 × 10⁻¹⁰)^3 ≈ 1.41 × 10⁻²⁹ m³ Step 2: Number of molecules in 1 mole = Avogadro's number, N_A = 6.022 × 10²³ Step 3: Total molecular volume = N_A × v_m = 6.022 × 10²³ × 1.41 × 10⁻²⁹ ≈ 8.5 × 10⁻⁶ m³ Step 4: Fraction of molecular volume to actual volume = (8.5 × 10⁻⁶) / (22.4 × 10⁻³) ≈ 3.8 × 10⁻⁴ Hence, the fraction of molecular volume to actual volume is approximately 3.8 × 10⁻⁴.

Explanation:

The molecular volume is calculated by assuming each molecule is a sphere with given diameter. Multiplying by Avogadro's number gives total molecular volume in 1 mole. Dividing by molar volume at STP gives the fraction.

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