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The Amazing World of Solutes, Solvents, and Solutions

🎓 Class 8📖 Curiosity📖 11 notes🧠 15 Q&A⏱️ ~17 min

The Amazing World of Solutes, Solvents, and SolutionsStudy Notes

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The Amazing World of Solutes, Solvents, and Solutions

Explanation

The Amazing World of Solutes, Solvents, and Solutions

This introductory section sets the stage for understanding the fundamental concepts of solutes, solvents, and solutions, which are essential in both everyday life and scientific contexts. It begins with a relatable example of Oral Rehydration Solution (ORS), a mixture of sugar and salt dissolved in water, used to treat dehydration. The uniform taste of ORS regardless of how much is consumed illustrates the concept of a uniform mixture, where the components are evenly distributed throughout. This contrasts with non-uniform mixtures, such as chalk powder or sand mixed with water, where the components are not evenly distributed and can be seen separately. The section encourages students to observe and question why some substances dissolve in water while others do not, and why water is considered a good solvent. It also prompts curiosity about the shapes of containers like water bottles and the behavior of mixtures, setting a foundation for exploring the science of mixing substances.

  • ORS is a uniform mixture of sugar, salt, and water with evenly distributed components.
  • Uniform mixtures where components are evenly distributed are called solutions.
  • Non-uniform mixtures have components that are not evenly distributed and can be seen separately.
  • Water is a common solvent in many solutions due to its ability to dissolve various solutes.
  • The section encourages inquiry into why some substances dissolve in water and others do not.
  • Observations of everyday mixtures help understand the nature of solutions and mixtures.
  • 📌 Solution: A uniform mixture where components are evenly distributed.
  • 📌 Solute: The substance that dissolves in a solvent.
  • 📌 Solvent: The substance in which solute dissolves.

9.1 What Are Solute, Solvent, and Solution?

Definition

9.1 What Are Solute, Solvent, and Solution?

This section defines the key terms solute, solvent, and solution, explaining their roles in forming uniform mixtures. A solution is a uniform mixture formed when a solute dissolves in a solvent. Typically, when a solid dissolves in a liquid, the solid is the solute and the liquid is the solvent. The solute particles disperse evenly throughout the solvent, creating a homogeneous mixture. When two liquids form a solution, the substance present in smaller quantity is considered the solute, and the one in larger quantity is the solvent. The section also introduces the idea that gases can form solutions, such as air, which is a mixture of gases uniformly distributed. An example from Indian cuisine is given: the sugar syrup (Chashni) in Gulab jamun, where a large amount of sugar (solid) dissolves in a small amount of water (liquid), yet water remains the solvent. This helps clarify that the solvent is generally the substance present in larger quantity, regardless of the amount of solute dissolved.

  • Solution is a uniform mixture formed by dissolving solute in solvent.
  • Solute is the component that dissolves; solvent is the component that dissolves the solute.
  • In solid-liquid solutions, the solid is usually the solute and the liquid the solvent.
  • In liquid-liquid solutions, the component in smaller amount is the solute.
  • Gaseous mixtures like air are also considered solutions.
  • Water is a common solvent even when solute quantity is large, as in sugar syrup.
  • 📌 Solute: Substance dissolved in a solvent.
  • 📌 Solvent: Substance that dissolves the solute.
  • 📌 Solution: A homogeneous mixture of solute and solvent.

9.2 How Much Solute Can a Fixed Amount of Solvent Dissolve?

Explanation

9.2 How Much Solute Can a Fixed Amount of Solvent Dissolve?

This section investigates the capacity of a solvent to dissolve solute, introducing the concepts of saturated and unsaturated solutions. Through Activity 9.1, students add increasing amounts of salt to a fixed volume of water, observing that initiall

Practice QuestionsThe Amazing World of Solutes, Solvents, and Solutions

Includes NCERT exercise questions with answers

Q1.1. State whether the statements given below are True [T] or False [F]. Correct the false statement(s). (i) Oxygen gas is more soluble in hot water rather than in cold water. (ii) A mixture of sand and water is a solution. (iii) The amount of space occupied by any object is called its mass. (iv) An unsaturated solution has more solute dissolved than a saturated solution. (v) The presence of different gases in the atmosphere is also a uniform mixture.

Answer:

Answers: (i) False. Oxygen gas is more soluble in cold water than in hot water. (ii) False. A mixture of sand and water is not a solution; it is a suspension. (iii) False. The amount of space occupied by an object is called its volume, not mass. (iv) False. An unsaturated solution has less solute dissolved than a saturated solution. (v) True. The atmosphere is a uniform mixture of different gases.

Explanation:

Step-by-step: (i) Solubility of gases decreases with increase in temperature, so oxygen is more soluble in cold water. (ii) Sand does not dissolve in water; hence, sand-water mixture is not a solution. (iii) Mass is the amount of matter; volume is the space occupied. (iv) Saturated solution contains maximum solute; unsaturated contains less. (v) Gases in atmosphere mix uniformly forming a homogeneous mixture.

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Q2.2. Fill in the blanks. (i) The volume of a solid can be measured by the method of displacement, where the solid is _______ in water and the _______ in water level is measured. (ii) The maximum amount of _______ dissolved in _______ at a particular temperature is called solubility at that temperature. (iii) Generally, the density _______ with increase in temperature. (iv) The solution in which glucose has completely dissolved in water, and no more glucose can dissolve at a given temperature, is called a _______ solution of glucose.

Answer:

(i) The volume of a solid can be measured by the method of displacement, where the solid is _immersed_ in water and the _rise_ in water level is measured. (ii) The maximum amount of _solute_ dissolved in _solvent_ at a particular temperature is called solubility at that temperature. (iii) Generally, the density _decreases_ with increase in temperature. (iv) The solution in which glucose has completely dissolved in water, and no more glucose can dissolve at a given temperature, is called a _saturated_ solution of glucose.

Explanation:

Step-by-step: (i) Displacement method involves immersing the solid in water and measuring how much the water level rises, which equals the volume of the solid. (ii) Solubility is defined as the maximum amount of solute dissolved in a solvent at a given temperature. (iii) Density usually decreases as temperature increases because volume expands. (iv) When no more solute can dissolve, the solution is saturated.

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Q3.3. You pour oil into a glass containing some water. The oil floats on top. What does this tell you? (i) Oil is denser than water (ii) Water is denser than oil (iii) Oil and water have the same density (iv) Oil dissolves in water
A.A) Oil is denser than water
B.B) Water is denser than oil
C.C) Oil and water have the same density
D.D) Oil dissolves in water

Answer:

Correct answer: (ii) Water is denser than oil. Explanation: Since oil floats on water, it means oil is less dense than water. Therefore, water is denser than oil.

Explanation:

When two liquids do not mix and one floats on the other, the one floating is less dense. Here, oil floats on water, so oil is less dense and water is denser.

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Q4.4. A stone sculpture weighs 225 g and has a volume of 90 cm³. Calculate its density and predict whether it will float or sink in water.

Answer:

Density = Mass / Volume = 225 g / 90 cm³ = 2.5 g/cm³. Since the density of water is 1 g/cm³, and the stone's density (2.5 g/cm³) is greater than water, the stone will sink in water.

Explanation:

Step 1: Calculate density using formula: Density = Mass / Volume = 225 g / 90 cm³ = 2.5 g/cm³ Step 2: Compare with water density (1 g/cm³): Since 2.5 > 1, the stone is denser and will sink.

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Q5.5. Which one of the following is the most appropriate statement, and why are the other statements not appropriate? (i) A saturated solution can still dissolve more solute at a given temperature. (ii) An unsaturated solution has dissolved the maximum amount of solute possible at a given temperature. (iii) No more solute can be dissolved into the saturated solution at that temperature. (iv) A saturated solution forms only at high temperatures.

Answer:

Correct statement: (iii) No more solute can be dissolved into the saturated solution at that temperature. Explanation: (i) Incorrect because a saturated solution cannot dissolve more solute at that temperature. (ii) Incorrect because an unsaturated solution has less than the maximum solute dissolved. (iv) Incorrect because saturated solutions can form at any temperature depending on solubility.

Explanation:

Step-by-step: - Saturated solution means maximum solute dissolved; no more can dissolve. - Unsaturated solution means more solute can still dissolve. - Saturated solutions are not restricted to high temperatures; they depend on solubility at that temperature.

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Q6.6. You have a bottle with a volume of 2 litres. You pour 500 mL of water into it. How much more water can the bottle hold?

Answer:

Total volume of bottle = 2 litres = 2000 mL Water poured = 500 mL Remaining volume = 2000 mL - 500 mL = 1500 mL Therefore, the bottle can hold 1500 mL more water.

Explanation:

Step 1: Convert litres to millilitres (1 litre = 1000 mL) 2 litres = 2000 mL Step 2: Subtract the volume of water poured from total volume 2000 mL - 500 mL = 1500 mL Step 3: The remaining volume is the capacity left for more water.

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Q7.7. An object has a mass of 400 g and a volume of 40 cm³. What is its density?

Answer:

Density = Mass / Volume = 400 g / 40 cm³ = 10 g/cm³.

Explanation:

Using the formula: Density = Mass / Volume = 400 g / 40 cm³ = 10 g/cm³

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Q8.8. Analyse Fig. 9.25a and 9.25b. Why does the unpeeled orange float, while the peeled one sinks? Explain.

Answer:

The unpeeled orange floats because the peel contains air pockets, making its overall density less than water. When the peel is removed, the orange's density increases as the air pockets are lost, making it denser than water, so it sinks.

Explanation:

Step-by-step: - The peel traps air, reducing the orange's density. - Lower density than water causes it to float. - Removing the peel removes air pockets, increasing density. - Higher density than water causes it to sink.

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