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Atoms

🎓 Class 12📖 Physics Part-II📖 9 notes🧠 15 Q&A⏱️ ~14 min

AtomsStudy Notes

NCERT-aligned · 9 notes · 3 shown free

Introduction

Explanation

Introduction

The chapter 'Atoms' begins by highlighting the fundamental importance of understanding the structure of matter at the microscopic level. Matter is composed of tiny particles called atoms, which are the basic building blocks of all substances. The study of atoms has evolved over centuries, starting from philosophical ideas to scientific models supported by experiments. The chapter traces the historical development of atomic models, emphasizing how experimental evidence has shaped our current understanding. Initially, atoms were considered indivisible particles, but later discoveries revealed their complex internal structure, including a dense nucleus and orbiting electrons. This understanding is crucial for explaining various physical and chemical phenomena, such as the nature of chemical bonds, emission spectra, and the behavior of gases. The chapter sets the stage for exploring key experiments and theories that led to the modern atomic model, including Rutherford’s alpha-particle scattering experiment and Bohr’s model of the hydrogen atom.

  • Atoms are the fundamental units of matter.
  • Historical development of atomic theory evolved from philosophical ideas to experimental science.
  • Atoms were once thought indivisible but later found to have internal structure.
  • Understanding atomic structure explains chemical and physical properties of matter.
  • The chapter introduces key experiments and models that shaped atomic theory.
  • 📌 Atom: The smallest unit of an element that retains its chemical properties.
  • 📌 Atomic model: A theoretical representation of the structure of an atom.

Rutherford’s α-particle scattering experiment

Explanation

Rutherford’s α-particle scattering experiment

This section describes the famous Geiger-Marsden experiment conducted under the guidance of Ernest Rutherford to investigate the structure of the atom. The experiment involved directing a beam of alpha (α) particles, which are helium nuclei with a charge of +2e and energy about 5.5 MeV, at a very thin gold foil. The apparatus was placed inside a vacuum chamber to prevent α-particles from scattering due to air molecules. A fluorescent screen surrounded the foil to detect scattered α-particles by producing tiny flashes of light when struck. The expectation based on the then-prevailing 'plum pudding' model was that α-particles would pass through the foil with minimal deflection because the positive charge was thought to be diffused throughout the atom. However, the experiment revealed that while most α-particles passed straight through, a small fraction were deflected at large angles, and some even bounced back. This unexpected result suggested the presence of a small, dense, positively charged nucleus at the center of the atom. The experiment was pivotal in disproving the plum pudding model and establishing the nuclear model of the atom.

  • Alpha particles (5.5 MeV) were directed at thin gold foil.
  • Most α-particles passed through with little or no deflection.
  • Some α-particles were deflected at large angles; a few bounced back.
  • The experiment was conducted in a vacuum chamber to avoid air scattering.
  • Detection was via a fluorescent screen producing flashes on α-particle impact.
  • 📌 Alpha particle (α-particle): A helium nucleus consisting of two protons and two neutrons, positively charged.
  • 📌 Scattering experiment: An experiment where particles are deflected by target atoms to study atomic structure.

Observations and conclusions from the scattering experiment

Explanation

Observations and conclusions from the scattering experiment

The Geiger-Marsden experiment yielded several important observations that revolutionized atomic theory. The majority of α-particles passed through the gold foil without any deflection, indicating that most of the atom is empty space. About 1 in 8000

Practice QuestionsAtoms

Includes NCERT exercise questions with answers

Q1.According to Bohr’s model of hydrogen atom, an electron can revolve round a nucleus indefinitely, if its path is
A.a perfect circle of any radius
B.a circle of constantly decreasing radius
C.a circle of an allowed radius
D.an ellipse

Answer:

a circle of an allowed radius

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Q2.De Broglie’s hypothesis gave an explanation for Bohr’s quantised orbits by bringing in the wave particle duality. According to this, the orbits correspond to circular standing waves in which the circumference of the orbit is
A.an integral multiple of wavelength
B.always equal to wavelength
C.independent of wavelength
D.an integral multiple of frequency

Answer:

an integral multiple of wavelength

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Q3.As an electron makes a transition from an excited state to the ground state of a hydrogen-like atom/ion
A.its kinetic energy increases but potential energy and total energy decreases
B.kinetic energy, potential energy and total energy decreases
C.kinetic energy decreases but potential energy and total energy increases
D.kinetic and total energy decreases but potential energy increases

Answer:

its kinetic energy increases but potential energy and total energy decreases

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Q4.Bohr’s theory of hydrogen atom could not completely explain the
A.diameter of H- atom
B.emission spectra
C.ionisation energy
D.fine structure of hydrogen spectrum

Answer:

fine structure of hydrogen spectrum

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Q5.The angular momentum of an electron in the third orbit of an atom is
A.3.15 x 10 -34 Js
B.2.15 x 10 -34 Js
C.3.15 x 10 -32 Js
D.2.15 x 10 -33 Js

Answer:

3.15 x 10 -34 Js

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Q6.The wavelength of second line of the Balmer series in the hydrogen spectrum is 486.1 nm . The wavelength of the first line of the Balmer series will be
A.652.2 nm
B.527.4 nm
C.686.9 nm
D.753.6 nm

Answer:

652.2 nm

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Q7.Which of the following transitions in hydrogen atom, emits photon of highest frequency?
A.n = 1 to n = 2
B.n = 2 to n = 6
C.n = 6 to n = 2
D.n = 2 to n = 1

Answer:

n = 2 to n = 1

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Q8.An alpha particle of energy 5 MeV is scattered through 180 0 by a fixed uranium nucleus. The distance of closest approach is of the order of
A.10 -10 m
B.10 -10 cm
C.10 -12 cm
D.10 -15 cm

Answer:

10 -12 cm

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