What is Application of Derivatives Class 12: Definition & Uses
By ConceptScroll Team · Published on 19 June 2026 · 4 min read
What is Application of Derivatives class 12? It is a crucial chapter in NCERT Mathematics that explains how derivatives help solve problems involving rates of change, maxima, minima, and tangents. This chapter is essential for Class 12 students aiming to master calculus concepts and excel in exams.
Understanding the Definition of Application of Derivatives
The application of derivatives involves using the derivative of a function to solve practical problems. In Class 12 NCERT Mathematics, this means applying the concept of differentiation to find:
- Rate of change of quantities
- Increasing and decreasing functions
- Local maxima and minima
- Tangents and normals to curves
A derivative, denoted as $\frac{dy}{dx}$, represents how a function $y=f(x)$ changes with respect to $x$. This fundamental idea helps students connect abstract calculus with real-world scenarios.
How Derivatives Help Identify Increasing and Decreasing Functions
One key application of derivatives is to determine where a function is increasing or decreasing:
- If $f'(x) > 0$ for an interval, the function is increasing there.
- If $f'(x) < 0$ for an interval, the function is decreasing there.
This helps in sketching graphs and understanding the behaviour of functions. For example, consider $f(x) = x^3 - 3x^2 + 2$:
$$f'(x) = 3x^2 - 6x$$
- For $x > 2$, $f'(x) > 0$ so $f$ is increasing.
- For $0 < x < 2$, $f'(x) < 0$ so $f$ is decreasing.
This analysis is vital for solving problems related to function behaviour in exams.
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Finding Maxima and Minima Using Derivatives
Maxima and minima are points where a function reaches its highest or lowest value locally. To find these:
1. Find the critical points by solving $f'(x) = 0$. 2. Use the second derivative test:
- If $f''(x) > 0$, the point is a local minimum.
- If $f''(x) < 0$, the point is a local maximum.
Example:
For $f(x) = x^2 - 4x + 3$:
- $f'(x) = 2x - 4$; set $2x - 4 = 0$ gives $x=2$.
- $f''(x) = 2 > 0$ so $x=2$ is a minimum.
This method is widely tested in Class 12 exams for optimization problems.
Using Derivatives to Find Tangents and Normals to Curves
Derivatives help find the slope of a curve at any point, which is essential for equations of tangents and normals.
- The slope of the tangent at $x=a$ is $m = f'(a)$.
- Equation of tangent: $y - f(a) = f'(a)(x - a)$.
- Equation of normal: $y - f(a) = -\frac{1}{f'(a)}(x - a)$.
Example:
For $y = x^2$ at $x=1$:
- $f'(x) = 2x$, so $f'(1) = 2$.
- Tangent: $y - 1 = 2(x - 1)$ or $y = 2x - 1$.
- Normal: $y - 1 = -\frac{1}{2}(x - 1)$ or $y = -\frac{1}{2}x + \frac{3}{2}$.
This application is important for geometry-related questions in Class 12.
Real-Life Applications of Derivatives in Class 12 Mathematics
Derivatives are not just theoretical; they solve real-world problems such as:
- Optimizing profit and cost: Finding maximum profit or minimum cost using maxima/minima.
- Physics: Calculating velocity and acceleration as derivatives of displacement.
- Economics: Marginal cost and revenue analysis.
- Engineering: Designing curves and slopes.
These applications demonstrate the practical importance of the chapter and help students appreciate the usefulness of calculus.
Comparison of Key Concepts in Application of Derivatives
Here’s a quick comparison table summarizing important concepts:
| Concept | Purpose | Formula / Condition |
|---|---|---|
| Increasing Function | Function rises with $x$ | $f'(x) > 0$ |
| Decreasing Function | Function falls with $x$ | $f'(x) < 0$ |
| Local Maxima | Highest point locally | $f'(x) = 0$, $f''(x) < 0$ |
| Local Minima | Lowest point locally | $f'(x) = 0$, $f''(x) > 0$ |
| Tangent to Curve | Line touching curve at one point | $y - f(a) = f'(a)(x - a)$ |
| Normal to Curve | Perpendicular to tangent | $y - f(a) = -\frac{1}{f'(a)}(x - a)$ |
This table helps students quickly revise key points before exams.
Frequently asked questions
What is the main idea of application of derivatives in Class 12?
It involves using derivatives to find rates of change, maxima, minima, tangents, and solve real-life problems.
How do derivatives help find maxima and minima?
By solving $f'(x)=0$ for critical points and using $f''(x)$ to determine if points are maxima or minima.
Can you give an example of using derivatives to find a tangent?
For $y=x^2$ at $x=1$, slope is $2$, tangent equation is $y=2x-1$.
Why is the application of derivatives important for Class 12 students?
It helps solve calculus problems in exams and understand real-world phenomena involving change and optimization.
What topics are covered under application of derivatives in NCERT Class 12?
Increasing/decreasing functions, maxima/minima, tangents/normals, and real-life applications.
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