ScienceClass 8Pressure, Winds, Storms, and Cyclones

Pressure, Winds, Storms, and Cyclones | Class 8 Science Notes

By ConceptScroll Team · Published on 17 July 2026 · 6 min read

Pressure, Winds, Storms, and Cyclones – this guide gives you a concise, exam-ready overview of Pressure, Winds, Storms, and Cyclones from Class 8 Science, written by ConceptScroll editors and reviewed against the latest NCERT textbook.

Pressure

Pressure is a fundamental concept that relates force and area. It is defined as the force exerted per unit area on a surface. This concept explains everyday observations such as why carrying a bag with broad straps feels more comfortable than with narrow straps, even if both bags weigh the same. The force due to the weight of the bag acts on the shoulder, but when the strap is narrow, the force is concentrated on a smaller area, resulting in higher pressure and discomfort. Conversely, broad straps distribute the force over a larger area, reducing the pressure and making it easier to carry the bag. This principle is expressed mathematically as Pressure = Force / Area, where the force is perpendicular to the surface.

The SI unit of force is newton (N), and the unit of area is square meter (m²). Therefore, the SI unit of pressure is newton per square meter (N/m²), also called pascal (Pa). For example, if a force of 100 N acts on an area of 2 m², the pressure exerted is 50 N/m² or 50 Pa.

This concept is applicable in various situations such as lifting water buckets with broad or narrow handles, where broad handles reduce pressure on the hands, making it easier to lift. Similarly, placing a cloth under loads carried on the head increases the area over which the force acts, reducing pressure and discomfort.

Pressure also explains why nails are easier to drive when struck on the pointed end rather than the flat head, and why sharp knives cut better than blunt ones. These examples show that a smaller area of force application results in higher pressure, facilitating cutting or piercing.

Liquids exert pressure as well, which depends on the height of the liquid column. This is why overhead water tanks are placed at a height—to increase water pressure at taps, ensuring a good flow. Liquids exert pressure in all directions, not just at the bottom, which can be observed by water spurting out from holes on the sides of a container.

In summary, pressure is a measure of how concentrated a force is on a surface, influencing many natural and practical phenomena.

📊 Diagram: Fig. 6.1 shows Megha and Pawan carrying bags with broad and narrow straps respectively, illustrating how strap width affects pressure on shoulders. Fig. 6.2 shows buckets with broad and narrow handles, demonstrating ease of lifting with broad handles. Fig. 6.3 depicts persons carrying loads on their heads with cloth pieces underneath to increase area and reduce pressure.

🧪 Activity: Activity 6.1 involves using two transparent pipes of different diameters with balloons attached, filled with water to the same height, to observe that pressure depends on the height of the water column, not the diameter.

🔗 Connection: This section lays the foundation for understanding pressure exerted by liquids and gases, leading to the study of atmospheric pressure and wind formation.

Frequently asked questions

1. Choose the correct statement. (i) Look at Fig. 6.21 carefully. Vessel R is filled with water. When pouring of water is stopped, the level of water will be (a) the highest in vessel P (b) the highest in vessel Q (c) the highest in vessel R (d) equal in all three vessels (ii) A rubber sucker (M) is pressed on a flat smooth surface and an identical sucker (N) is pressed on a rough surface: (a) Both M and N will stick to their surfaces. (b) Both M and N will not stick to their surfaces. (c) M will stick but N will not stick. (d) M will not stick but N will stick. (iii) A water tank is placed on the roof of a building at a height 'H'. To get water with more pressure on the ground floor, one has to (a) increase the height 'H' at which the tank is placed. (b) decrease the height 'H' at which the tank is placed. (c) replace the tank with another tank of the same height that can hold more water. (d) replace the tank with another tank of the same height that can hold less water. (iv) Two vessels, A and B contain water up to the same level as shown in Fig. 6.22. PA and PB is the pressure at the bottom of the vessels. FA and FB is the force exerted by the water at the bottom of the vessels A and B. (a) PA = PB, FA = FB (b) PA = PB, FA < FB (c) PA < PB, FA = FB (d) PA > PB, FA > FB

1.(i) (d) equal in all three vessels. Explanation: The water level will be equal in all connected vessels due to the principle of communicating vessels.

(ii) (c) M will stick but N will not stick. Explanation: A rubber sucker sticks to a smooth surface because of air pressure difference; on a rough surface, air can enter, so it won't stick.

(iii) (a) increase the height 'H' at which the tank is placed. Explanation: Pressure due to water depends on height of water column, so increasing height i

2. State whether the following statements are True [T] or False [F]. (i) Air flows from a region of higher pressure to a region of lower pressure. (ii) Liquids exert pressure only at the bottom of a container. (iii) Weather is stormy at the eye of a cyclone. (iv) During a thunderstorm, it is safer to be in a car.

(i) True. Air moves from high to low pressure causing wind. (ii) False. Liquids exert pressure in all directions, not only at the bottom. (iii) False. The eye of a cyclone is calm with low pressure. (iv) True. Being inside a car is safer during thunderstorms as it acts like a Faraday cage.

3. Fig. 6.23a shows a boy lying horizontally, and Fig. 6.23b shows the boy standing vertically on a loose sand bed. In which case does the boy sink more in sand? Give reasons.

The boy sinks more when standing vertically (Fig. 6.23b). Reason: Pressure is force per unit area. When standing, the boy's weight is concentrated on a smaller area (feet), increasing pressure on sand, causing him to sink more. When lying horizontally, the weight is distributed over a larger area, reducing pressure and sinking.

4. An elephant stands on four feet. If the area covered by one foot is 0.25 m², calculate the pressure exerted by the elephant on the ground if its weight is 20000 N.

Given: Weight, W = 20000 N Area per foot, A_foot = 0.25 m² Number of feet = 4 Total area, A_total = 4 × 0.25 = 1 m²

Pressure, P = Force / Area = W / A_total = 20000 N / 1 m² = 20000 Pa

Therefore, the pressure exerted by the elephant on the ground is 20000 pascals (Pa).

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