Mathematics | Class 11 Mathematics Notes
By ConceptScroll Team · Published on 17 July 2026 · 3 min read
Mathematics – this guide gives you a concise, exam-ready overview of Mathematics from Class 11 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.
4.3 Algebra of Complex Numbers
This section develops the algebraic operations on complex numbers, including addition, subtraction, multiplication, and division, along with their properties.
Addition: For two complex numbers z₁ = a + ib and z₂ = c + id, their sum is defined as z₁ + z₂ = (a + c) + i(b + d), which is also a complex number. Addition satisfies closure, commutativity, associativity, existence of additive identity (0 + i0), and additive inverses (-a - ib).
Subtraction: Defined as z₁ - z₂ = z₁ + (-z₂), where -z₂ is the additive inverse of z₂.
Multiplication: For z₁ = a + ib and z₂ = c + id, the product is z₁z₂ = (ac - bd) + i(ad + bc). Multiplication also satisfies closure, commutativity, associativity, existence of multiplicative identity (1 + i0), multiplicative inverses for non-zero complex numbers, and distributive laws.
Division: For z₂ ≠ 0, division is defined as z₁ / z₂ = z₁ × (1 / z₂), where the multiplicative inverse of z₂ is (a / (a² + b²)) + i(-b / (a² + b²)) for z₂ = a + ib.
Power of i: Powers of i cycle every four steps: i⁰ = 1, i¹ = i, i² = -1, i³ = -i, i⁴ = 1, and so on. Negative powers are defined similarly.
Square roots of negative real numbers: The square roots of -a (a > 0) are ±√a i. The symbol √(-a) is taken as √a i.
Identities: Algebraic identities such as (z₁ + z₂)² = z₁² + 2z₁z₂ + z₂² hold for complex numbers, and similar expansions for cubes and differences are valid.
Several examples illustrate these operations and identities, including expressing complex expressions in a + ib form and computing powers.
📊 Diagram: No specific diagrams in this section.
🧪 Activity: No activity in this section.
🔗 Connection: Leads to the geometric interpretation of complex numbers in the Argand plane in section 4.5.
Frequently asked questions
1. $(5i)\left(-\frac{3}{5}i\right)$
Given: (5i)\left(-\frac{3}{5}i\right)
Step 1: Multiply the constants: 5 (-3/5) = -3 Step 2: Multiply the imaginary units: i i = i^2 = -1 Step 3: So, (5i)(-3/5 i) = -3 * (-1) = 3
Answer: 3
2. $i^9 + i^{19}$
Recall powers of i cycle every 4: i^1 = i i^2 = -1 i^3 = -i i^4 = 1
Calculate i^9: 9 mod 4 = 1, so i^9 = i
Calculate i^{19}: 19 mod 4 = 3, so i^{19} = -i
Sum: i + (-i) = 0
Answer: 0
3. $i^{-39}$
Recall powers of i cycle every 4. First, convert negative power: i^{-39} = 1 / i^{39}
Calculate 39 mod 4: 39 mod 4 = 3 So, i^{39} = i^3 = -i
Therefore, i^{-39} = 1 / (-i) = -1 / i
Multiply numerator and denominator by i: = (-1 / i) * (i / i) = (-i) / (i^2) = (-i) / (-1) = i
Answer: i
4. $3(7 + i7) + i(7 + i7)$
Given expression: 3(7 + 7i) + i(7 + 7i)
Step 1: Expand each term: 3(7 + 7i) = 21 + 21i
Step 2: i(7 + 7i) = 7i + 7i^2 = 7i + 7(-1) = 7i - 7
Step 3: Add the two results: (21 + 21i) + (7i - 7) = (21 - 7) + (21i + 7i) = 14 + 28i
Answer: 14 + 28i
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