MathematicsClass 10Mathematics

Mathematics | Class 10 Mathematics Notes

By ConceptScroll Team · Published on 17 July 2026 · 4 min read

Mathematics – this guide gives you a concise, exam-ready overview of Mathematics from Class 10 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.

2.1 Introduction

This section revisits the concept of polynomials in one variable, a topic introduced in Class IX. A polynomial p(x) in variable x is an algebraic expression involving terms with non-negative integer powers of x and real coefficients. The degree of a polynomial is the highest power of the variable present in it. For example, 4x + 2 is a polynomial of degree 1, 2y² - 3y + 4 is degree 2, 5x³ - 4x² + x - √2 is degree 3, and 7u⁶ - (3/2)u³ + 4u² + u - 8 is degree 6. Expressions such as 1/(x - 1), √x + 2, or 1/(x² + 2x + 3) are not polynomials because they involve negative or fractional powers or variables in denominators. Polynomials are classified by their degree: degree 1 polynomials are linear, degree 2 are quadratic, and degree 3 are cubic. Linear polynomials have the form ax + b where a ≠ 0; quadratic polynomials have the form ax² + bx + c with a ≠ 0; cubic polynomials have the form ax³ + bx² + cx + d with a ≠ 0. The section also introduces the concept of the value of a polynomial at a given point k, denoted p(k), obtained by substituting x = k in p(x). A zero of a polynomial is a value k for which p(k) = 0. For example, the polynomial x² - 3x - 4 has zeros at x = -1 and x = 4 because p(-1) = 0 and p(4) = 0. The zero of a linear polynomial ax + b is -b/a, showing a direct relation between zeros and coefficients. The section poses the question of whether such relationships exist for polynomials of higher degrees, which will be explored further. Finally, it introduces the division algorithm for polynomials as a topic to be studied.

🔗 Connection: Leads to the next section which explores the geometrical meaning of zeros of polynomials by studying their graphs.

Frequently asked questions

1. The graphs of $y = p(x)$ are given in Fig. 2.10 below, for some polynomials $p(x)$ . Find the number of zeroes of $p(x)$ , in each case. (i) (ii) (iii) (iv) (v) (vi)

To find the number of zeroes of each polynomial from the graphs given in Fig. 2.10, observe the points where the graph intersects the x-axis. Each intersection corresponds to a zero of the polynomial.

(i) Count the number of x-intercepts in graph (i). (ii) Count the number of x-intercepts in graph (ii). (iii) Count the number of x-intercepts in graph (iii). (iv) Count the number of x-intercepts in graph (iv). (v) Count the number of x-intercepts in graph (v). (vi) Count the number of x-intercep

1. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. (i) x^{2} - 2x - 8 (ii) 4s^{2} - 4s + 1 (iii) 6x^{2} - 3 - 7x (iv) 4u^{2} + 8u (v) t^2 - 15 (vi) 3x^{2} - x - 4

Solution:

(i) Polynomial: x^2 - 2x - 8 Sum of zeroes, α + β = -b/a = -(-2)/1 = 2 Product of zeroes, αβ = c/a = -8/1 = -8

Find zeroes by factorization: x^2 - 2x - 8 = (x - 4)(x + 2) Zeroes are 4 and -2 Sum = 4 + (-2) = 2, Product = 4 * (-2) = -8 Relationship verified.

(ii) Polynomial: 4s^2 - 4s + 1 Sum = -b/a = -(-4)/4 = 1 Product = c/a = 1/4

Find zeroes using quadratic formula: s = [4 ± sqrt(16 - 16)] / (2*4) = 4/(8) = 0.5 Since discriminant is zero, both zeroes are equal: 0.5 and 0.5 Sum =

2. Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively. (i) \frac{1}{4}, -1 (ii) \sqrt{2}, \frac{1}{3} (iii) 0, \sqrt{5} (iv) 1, 1 (v) -\frac{1}{4}, \frac{1}{4} (vi) 4, 1

Solution:

Recall: For quadratic polynomial with zeroes α and β, Sum = α + β = -b/a and Product = αβ = c/a.

We take a = 1 for simplicity, so polynomial is x^2 - (sum)x + product.

(i) Sum = 1/4, Product = -1 Polynomial: x^2 - (1/4)x - 1

(ii) Sum = √2, Product = 1/3 Polynomial: x^2 - (\sqrt{2})x + 1/3

(iii) Sum = 0, Product = √5 Polynomial: x^2 - 0*x + \sqrt{5} = x^2 + \sqrt{5}

(iv) Sum = 1, Product = 1 Polynomial: x^2 - x + 1

(v) Sum = -1/4, Product = 1/4 Polynomial: x^2 - (-1/4)x + 1/4 = x

Which of the following expressions is NOT a polynomial?

\sqrt{x} + 2

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