MathematicsClass 10Mathematics

Mathematics | Class 10 Mathematics Notes

By ConceptScroll Team · Published on 17 July 2026 · 5 min read

Mathematics – this guide gives you a concise, exam-ready overview of Mathematics from Class 10 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.

2.2 Geometrical Meaning of the Zeroes of a Polynomial

This section explains the importance of zeros of polynomials through their geometric interpretation as points where the graph of the polynomial intersects the x-axis. For a linear polynomial y = ax + b (a ≠ 0), the graph is a straight line intersecting the x-axis at one point (-b/a, 0), which corresponds to the zero of the polynomial. For example, y = 2x + 3 intersects the x-axis at (-3/2, 0). This is illustrated in Fig. 2.1 and Table 2.1, showing values of y for x = -2 and 2. For quadratic polynomials y = ax² + bx + c (a ≠ 0), the graph is a parabola opening upwards if a > 0 or downwards if a < 0. The zeros of the quadratic polynomial are the x-coordinates where the parabola intersects the x-axis. Using the example y = x² - 3x - 4, Table 2.2 lists y-values for various x, showing zeros at x = -1 and x = 4, confirmed by the graph in Fig. 2.2. Three cases arise for quadratic polynomials: (i) two distinct zeros where the parabola cuts the x-axis at two points (Fig. 2.3), (ii) one zero where the parabola is tangent to the x-axis (Fig. 2.4), and (iii) no zeros where the parabola lies entirely above or below the x-axis (Fig. 2.5). For cubic polynomials y = ax³ + bx² + cx + d, the graph can intersect the x-axis at up to three points, corresponding to up to three zeros. The example y = x³ - 4x has zeros at -2, 0, and 2, as shown in Table 2.3 and Fig. 2.6. Other examples include y = x³ and y = x³ - x² with zeros at 0 and 0,1 respectively (Figs. 2.7 and 2.8). The section concludes with the general remark that a polynomial of degree n has at most n zeros, corresponding to at most n x-axis intersections.

📊 Diagram: [figure_1] [figure_2] [figure_3] [figure_4] [figure_5] [figure_6] [figure_9] [figure_10] [table_1] [table_2] [table_3] Fig. 2.1; Fig. 2.2; Fig. 2.3; Fig. 2.4; Fig. 2.5; Fig. 2.6; Fig. 2.7; Fig. 2.8; Table on page 3 (2×3); Table on page 4 (2×9); Table on page 6 (2×6)

🧪 Activity: Students are encouraged to plot values of polynomials for various x on graph paper to visualize zeros as x-axis intersections.

🔗 Connection: Prepares for Exercise 2.1 on identifying zeros from graphs and leads to study of relationships between zeros and coefficients.

Frequently asked questions

1. The graphs of $y = p(x)$ are given in Fig. 2.10 below, for some polynomials $p(x)$ . Find the number of zeroes of $p(x)$ , in each case. (i) (ii) (iii) (iv) (v) (vi)

To find the number of zeroes of each polynomial from the graphs given in Fig. 2.10, observe the points where the graph intersects the x-axis. Each intersection corresponds to a zero of the polynomial.

(i) Count the number of x-intercepts in graph (i). (ii) Count the number of x-intercepts in graph (ii). (iii) Count the number of x-intercepts in graph (iii). (iv) Count the number of x-intercepts in graph (iv). (v) Count the number of x-intercepts in graph (v). (vi) Count the number of x-intercep

1. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. (i) x^{2} - 2x - 8 (ii) 4s^{2} - 4s + 1 (iii) 6x^{2} - 3 - 7x (iv) 4u^{2} + 8u (v) t^2 - 15 (vi) 3x^{2} - x - 4

Solution:

(i) Polynomial: x^2 - 2x - 8 Sum of zeroes, α + β = -b/a = -(-2)/1 = 2 Product of zeroes, αβ = c/a = -8/1 = -8

Find zeroes by factorization: x^2 - 2x - 8 = (x - 4)(x + 2) Zeroes are 4 and -2 Sum = 4 + (-2) = 2, Product = 4 * (-2) = -8 Relationship verified.

(ii) Polynomial: 4s^2 - 4s + 1 Sum = -b/a = -(-4)/4 = 1 Product = c/a = 1/4

Find zeroes using quadratic formula: s = [4 ± sqrt(16 - 16)] / (2*4) = 4/(8) = 0.5 Since discriminant is zero, both zeroes are equal: 0.5 and 0.5 Sum =

2. Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively. (i) \frac{1}{4}, -1 (ii) \sqrt{2}, \frac{1}{3} (iii) 0, \sqrt{5} (iv) 1, 1 (v) -\frac{1}{4}, \frac{1}{4} (vi) 4, 1

Solution:

Recall: For quadratic polynomial with zeroes α and β, Sum = α + β = -b/a and Product = αβ = c/a.

We take a = 1 for simplicity, so polynomial is x^2 - (sum)x + product.

(i) Sum = 1/4, Product = -1 Polynomial: x^2 - (1/4)x - 1

(ii) Sum = √2, Product = 1/3 Polynomial: x^2 - (\sqrt{2})x + 1/3

(iii) Sum = 0, Product = √5 Polynomial: x^2 - 0*x + \sqrt{5} = x^2 + \sqrt{5}

(iv) Sum = 1, Product = 1 Polynomial: x^2 - x + 1

(v) Sum = -1/4, Product = 1/4 Polynomial: x^2 - (-1/4)x + 1/4 = x

Which of the following expressions is NOT a polynomial?

\sqrt{x} + 2

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