Moving Charges and Magnetism

What is the Weightage of Moving Charges and Magnetism Class 12 in Physics Exams

By ConceptScroll Team · Published on 19 June 2026 · 4 min read

The weightage of Moving Charges and Magnetism Class 12 in Physics exams typically ranges from 10 to 14 marks. This chapter covers fundamental concepts essential for CBSE board exams and competitive tests, making it crucial for students to understand and practice thoroughly.

Overview of Moving Charges and Magnetism in Class 12 Physics

The chapter Moving Charges and Magnetism is a vital part of the Class 12 NCERT Physics syllabus. It introduces students to the magnetic effects of electric currents and the forces experienced by moving charges in magnetic fields. Key topics include:

  • Magnetic field and magnetic force
  • Motion of charged particles in magnetic fields
  • Biot-Savart law and Ampere’s circuital law
  • Force on current-carrying conductors

Understanding these concepts helps build a strong foundation for electromagnetism and related applications in physics.

What is the Weightage of Moving Charges and Magnetism Class 12 in CBSE Exams?

In the CBSE Class 12 Physics board exams, the weightage of Moving Charges and Magnetism typically falls between 10 and 14 marks out of 70 total marks for the subject. This makes it one of the moderately high scoring chapters.

The marks are distributed across:

  • Short answer questions (2-3 marks each)
  • Numerical problems (3-5 marks)
  • Long answer questions (5 marks)

Focusing on this chapter can significantly boost your overall Physics score due to its clear concepts and formula-based questions.

Want to test yourself on Moving Charges and Magnetism? Try our free quiz →

Important Concepts and Formulas to Focus On

To score well in Moving Charges and Magnetism, students must master the following concepts and formulas:

  • Magnetic Force on a Moving Charge:

$$\vec{F} = q(\vec{v} \times \vec{B})$$ where $q$ is charge, $\vec{v}$ velocity, and $\vec{B}$ magnetic field.

  • Force on a Current-Carrying Conductor:

$$F = BIL \sin \theta$$ where $I$ is current, $L$ length of conductor, and $\theta$ angle between $B$ and $L$.

  • Biot-Savart Law:

$$d\vec{B} = \frac{\mu_0}{4\pi} \frac{I d\vec{l} \times \hat{r}}{r^2}$$

  • Ampere’s Circuital Law:

$$\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{enc}$$

Understanding these formulas and their applications through numerical problems is key to exam success.

Comparison of Marks Distribution in Moving Charges and Magnetism vs Other Chapters

Here is a comparison of typical marks distribution for Moving Charges and Magnetism and other important Class 12 Physics chapters:

ChapterApproximate MarksImportance Level
Moving Charges and Magnetism10 - 14High
Electrostatics12 - 15High
Current Electricity10 - 12Moderate
Magnetism and Matter6 - 8Moderate

This table shows that Moving Charges and Magnetism holds substantial weightage, making it essential to prepare well.

Tips to Prepare Moving Charges and Magnetism Effectively for Class 12 Exams

To maximize your score in this chapter, follow these preparation tips:

  • Understand Concepts: Focus on the physical meaning behind formulas rather than rote memorization.
  • Practice Numerical Problems: Solve all NCERT examples and additional problems to gain confidence.
  • Revise Diagrams: Draw and label diagrams like magnetic field lines and current loops clearly.
  • Use Flashcards: Create flashcards for formulas and important definitions.
  • Attempt Previous Year Questions: This helps identify frequently asked questions and exam patterns.

Consistent practice and revision are crucial for mastering this chapter.

Worked Example: Calculating Force on a Moving Charge in a Magnetic Field

Problem: A charge of $+2 \mu C$ moves with a velocity of $3 \times 10^6$ m/s perpendicular to a magnetic field of strength 0.5 T. Calculate the magnetic force acting on the charge.

Solution:

Given:

  • $q = +2 \times 10^{-6}$ C
  • $v = 3 \times 10^6$ m/s
  • $B = 0.5$ T
  • Angle $\theta = 90^\circ$ (perpendicular)

Formula:

$$F = qvB \sin \theta$$

Calculate:

$$F = 2 \times 10^{-6} \times 3 \times 10^6 \times 0.5 \times \sin 90^\circ$$ $$F = 2 \times 10^{-6} \times 3 \times 10^6 \times 0.5 \times 1 = 3 \text{ N}$$

Answer: The magnetic force on the charge is 3 Newtons.

Frequently asked questions

What is the weightage of Moving Charges and Magnetism in Class 12 Physics?

It carries around 10 to 14 marks in the CBSE Class 12 Physics exam.

Which formulas are important in the Moving Charges and Magnetism chapter?

Key formulas include magnetic force on moving charges, force on current-carrying conductors, Biot-Savart law, and Ampere’s circuital law.

How can I prepare effectively for this chapter?

Understand concepts, practice NCERT problems, revise diagrams, and solve previous year questions.

Are numerical problems important in this chapter?

Yes, numerical problems carry significant marks and help in understanding concepts practically.

Is this chapter important for competitive exams too?

Yes, concepts from Moving Charges and Magnetism are frequently tested in competitive exams like JEE.

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