What is the Weightage of Application of Integrals Class 12 in CBSE Exams?
By ConceptScroll Team · Published on 19 June 2026 · 4 min read
The weightage of Application of Integrals Class 12 in CBSE Mathematics exams typically ranges from 7 to 10 marks. This chapter is crucial for understanding practical uses of integrals, and students should focus on key concepts, formulas, and solving NCERT problems to score well.
Understanding the Weightage of Application of Integrals in Class 12 Exams
In the CBSE Class 12 Mathematics exam, the chapter "Application of Integrals" holds significant importance. Typically, this chapter contributes around 7 to 10 marks out of the total 80 marks in the Mathematics paper. This weightage reflects the chapter’s relevance in testing students' understanding of integral calculus applications.
The questions can range from short answer type to long answer type, including problems on finding areas between curves and volumes of solids of revolution. Since the chapter is application-based, it tests both conceptual understanding and problem-solving skills.
Students should allocate sufficient time to practice this chapter as it carries a moderate weightage and can boost overall exam scores.
Key Concepts Covered in Application of Integrals for Class 12 NCERT
The chapter covers essential concepts that connect integration with real-world problems. Important topics include:
- Area under curves: Calculating the area bounded by a curve and the x-axis or between two curves.
- Volume of solids of revolution: Using integrals to find volumes when a region is rotated about an axis.
- Properties of definite integrals: Understanding how definite integrals behave and their applications.
Formulas to remember:
- Area between curve and x-axis:
$$ A = \int_a^b |f(x)| \, dx $$
- Area between two curves:
$$ A = \int_a^b [f(x) - g(x)] \, dx $$
- Volume of solid of revolution about x-axis:
$$ V = \pi \int_a^b [f(x)]^2 \, dx $$
Mastering these concepts is vital for solving exam problems effectively.
Want to test yourself on Application of Integrals? Try our free quiz →
Tips to Prepare Application of Integrals Chapter for Class 12 Exams
To excel in this chapter, students should follow these preparation strategies:
- Understand the theory: Grasp the fundamental definitions and theorems related to definite integrals.
- Practice NCERT examples: Solve all solved examples in the NCERT textbook carefully.
- Attempt all exercises: Complete all end-of-chapter exercises to cover a variety of problem types.
- Use diagrams: Draw clear graphs and figures to visualize the problem.
- Memorize key formulas: Keep important formulas handy for quick recall.
- Solve previous year questions: Familiarize yourself with the exam pattern and frequently asked questions.
Consistent practice will help build confidence and improve accuracy.
Comparison of Application of Integrals with Other Class 12 Maths Chapters
Here's a comparison of the weightage and focus areas of Application of Integrals with other major Class 12 Maths chapters:
| Chapter | Approximate Weightage (Marks) | Focus Area |
|---|---|---|
| Application of Integrals | 7-10 | Area, volume, definite integrals |
| Differential Equations | 8-10 | Solving first order and higher order differential equations |
| Vector Algebra | 6-8 | Vectors, dot and cross products |
| Linear Programming | 6-8 | Optimization problems |
This comparison shows that Application of Integrals holds a moderate but important share in the exam, emphasizing practical calculus applications.
Worked Example: Finding Area Between Two Curves Using Integrals
Let's solve a typical problem from the Application of Integrals chapter:
Problem: Find the area bounded between the curves $y = x^2$ and $y = 4x - x^2$.
Solution:
1. Find the points of intersection by equating:
$$ x^2 = 4x - x^2 $$ $$ 2x^2 - 4x = 0 $$ $$ 2x(x - 2) = 0 $$ So, $x = 0$ or $x = 2$.
2. Set up the integral for area:
$$ A = \int_0^2 [(4x - x^2) - x^2] \, dx = \int_0^2 (4x - 2x^2) \, dx $$
3. Calculate the integral:
$$ = \left[2x^2 - \frac{2x^3}{3}\right]_0^2 = \left(2 \times 4 - \frac{2 \times 8}{3}\right) - 0 = 8 - \frac{16}{3} = \frac{24 - 16}{3} = \frac{8}{3} $$
Answer: The area bounded between the curves is $\frac{8}{3}$ square units.
This example illustrates the step-by-step approach to solving area problems using integrals.
Common Mistakes to Avoid While Studying Application of Integrals
Students often make errors that can be easily avoided:
- Ignoring limits of integration: Always find correct intersection points before integrating.
- Sign errors: Pay attention to which curve is on top to avoid negative areas.
- Skipping diagrams: Visual representation helps understand the problem better.
- Memorizing without understanding: Focus on conceptual clarity rather than rote learning.
- Not practicing enough: Lack of practice leads to mistakes in complex problems.
Avoiding these mistakes will improve accuracy and exam performance.
Frequently asked questions
What is the weightage of Application of Integrals in Class 12 CBSE exams?
The chapter typically carries 7 to 10 marks in the Class 12 CBSE Mathematics exam.
Which topics are important in Application of Integrals for Class 12?
Key topics include area under curves, volume of solids of revolution, and properties of definite integrals.
How can I prepare effectively for Application of Integrals chapter?
Understand concepts, practice NCERT examples, solve exercises, and memorize key formulas.
Are diagrams necessary in solving Application of Integrals problems?
Yes, diagrams help visualize problems and reduce calculation errors.
Is Application of Integrals a difficult chapter in Class 12 Maths?
It can be challenging but regular practice and conceptual clarity make it manageable.
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