What is Application of Integrals Class 12: Definition & Uses
By ConceptScroll Team · Published on 19 June 2026 · 5 min read
What is Application of Integrals class 12? It is a crucial chapter in NCERT Mathematics that deals with using integrals to find areas, volumes, and other quantities. This topic helps students solve real-world problems by applying integral calculus.
Understanding the Definition of Application of Integrals
The Application of Integrals in Class 12 Mathematics refers to using definite integrals to solve practical problems such as finding areas, volumes, and lengths. Integrals help calculate quantities that are not easily measured by simple formulas. In NCERT, this chapter introduces how integrals can be applied beyond theoretical calculus, making it a valuable tool for various fields.
Key points:
- Integrals sum infinitely small quantities to find total value.
- Definite integrals evaluate the area under a curve between two limits.
- Applications include areas between curves, volumes of solids, and more.
This chapter builds on your knowledge of integration from Class 11 and extends it to real-world applications.
Finding Area Under Curves Using Integrals
One of the primary applications of integrals is to find the area bounded by curves and the x-axis or between two curves.
Formula for Area Between Curve and X-axis
For a continuous function $f(x)$ on $[a, b]$, the area under the curve is:
$$ ext{Area} = \int_a^b |f(x)| \, dx$$
If $f(x)$ is positive in $[a,b]$, then:
$$ ext{Area} = \int_a^b f(x) \, dx$$
Area Between Two Curves
If $f(x)$ and $g(x)$ are two functions such that $f(x) \geq g(x)$ on $[a,b]$, then:
$$ ext{Area} = \int_a^b [f(x) - g(x)] \, dx$$
#### Worked Example: Find the area bounded by $y = x^2$ and $y = x + 2$.
- Find points of intersection by equating: $x^2 = x + 2 \Rightarrow x^2 - x - 2 = 0$
- Roots: $x = 2$ and $x = -1$
- Area:
$$\int_{-1}^2 [(x + 2) - x^2] \, dx = \left[ \frac{x^2}{2} + 2x - \frac{x^3}{3} \right]_{-1}^2 = \frac{9}{2}$$
Want to test yourself on Application of Integrals? Try our free quiz →
Calculating Volume of Solids of Revolution
Application of integrals also includes finding the volume of solids formed by rotating a curve around an axis, called solids of revolution.
Volume About X-axis
If the curve $y = f(x)$ is rotated about the x-axis from $x=a$ to $x=b$, the volume is:
$$V = \pi \int_a^b [f(x)]^2 \, dx$$
Volume About Y-axis
If the curve $x = g(y)$ is rotated about the y-axis from $y=c$ to $y=d$, the volume is:
$$V = \pi \int_c^d [g(y)]^2 \, dy$$
#### Worked Example: Find the volume of the solid formed by rotating the curve $y = \sqrt{x}$ from $x=0$ to $x=4$ about the x-axis.
$$V = \pi \int_0^4 (\sqrt{x})^2 \, dx = \pi \int_0^4 x \, dx = \pi \left[ \frac{x^2}{2} \right]_0^4 = \pi \times \frac{16}{2} = 8\pi$$
Comparing Area and Volume Formulas in Application of Integrals
Understanding the difference between area and volume calculations using integrals is essential.
| Quantity | Formula | Description |
|---|---|---|
| Area under curve | $\int_a^b f(x) \, dx$ | Area between curve and x-axis |
| Area between curves | $\int_a^b [f(x) - g(x)] \, dx$ | Area between two curves |
| Volume of solid (x-axis) | $\pi \int_a^b [f(x)]^2 \, dx$ | Volume by rotating curve about x-axis |
| Volume of solid (y-axis) | $\pi \int_c^d [g(y)]^2 \, dy$ | Volume by rotating curve about y-axis |
This table helps students quickly identify the correct integral formula for different applications.
Other Important Applications in Class 12 NCERT
Besides area and volume, integrals are used in other applications such as:
- Length of a curve: The length $L$ of a curve $y=f(x)$ from $x=a$ to $x=b$ is:
$$L = \int_a^b \sqrt{1 + \left( \frac{dy}{dx} \right)^2} \, dx$$
- Average value of a function:
$$f_{avg} = \frac{1}{b - a} \int_a^b f(x) \, dx$$
- Work done by a variable force: If force $F(x)$ varies with position $x$, work done moving from $a$ to $b$ is:
$$W = \int_a^b F(x) \, dx$$
These applications show the versatility of integrals in solving physical and mathematical problems.
Tips for Solving Application of Integrals Problems in Exams
To excel in Application of Integrals questions in Class 12 NCERT exams, keep these tips in mind:
- Understand the problem: Identify whether you need area, volume, length, or work.
- Sketch the graph: Visualizing curves helps set correct limits and functions.
- Set correct limits: Determine intersection points or given interval clearly.
- Choose the right formula: Refer to the comparison table for formulas.
- Simplify integrand: Algebraic simplification before integration saves time.
- Practice problems: Regular practice improves speed and accuracy.
By following these steps, students can confidently tackle application-based integral problems.
Frequently asked questions
What is the main purpose of Application of Integrals in Class 12?
It helps calculate areas, volumes, lengths, and other quantities using definite integrals.
How do you find the area between two curves using integrals?
Subtract the lower function from the upper function and integrate between the intersection points.
What formula is used to find the volume of a solid of revolution?
Volume about x-axis is $\pi \int_a^b [f(x)]^2 dx$; about y-axis is $\pi \int_c^d [g(y)]^2 dy$.
Can integrals be used to find the length of a curve?
Yes, length is found using $L = \int_a^b \sqrt{1 + (dy/dx)^2} dx$.
Why is Application of Integrals important for NCERT Class 12 exams?
It is a key chapter with practical problems frequently asked in exams.
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