PhysicsClass 12Semiconductor Electronics: Materials, Devices And Simple Circuits 14.1 Introduction

Semiconductor Electronics: Materials, Devices And Simple Circuits 14.1 Introduction | Class 12 Physics Notes

By ConceptScroll Team · Published on 17 July 2026 · 5 min read

Semiconductor Electronics: Materials, Devices And Simple Circuits 14.1 Introduction – this guide gives you a concise, exam-ready overview of Semiconductor Electronics: Materials, Devices And Simple Circuits 14.1 Introduction from Class 12 Physics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.

14.4 EXTRINSIC SEMICONDUCTOR

Intrinsic semiconductors have low conductivity at room temperature, limiting their practical use in electronic devices. To enhance conductivity, small amounts of impurities (dopants) are deliberately introduced into the pure semiconductor, a process called doping. The resulting materials are called extrinsic semiconductors or impurity semiconductors.

Dopants must have atomic sizes similar to the host semiconductor atoms to fit into the crystal lattice without significant distortion. For tetravalent semiconductors like Si and Ge, two types of dopants are used:

(i) Pentavalent dopants (valency 5) such as Arsenic (As), Antimony (Sb), Phosphorus (P) create n-type semiconductors.

(ii) Trivalent dopants (valency 3) such as Indium (In), Boron (B), Aluminium (Al) create p-type semiconductors.

In n-type semiconductors, pentavalent dopant atoms replace Si or Ge atoms in the lattice. Four of their five valence electrons form covalent bonds with neighboring atoms, while the fifth electron is loosely bound and easily freed at room temperature, contributing to conduction. These dopants are called donor impurities. The ionization energy to free this electron (~0.01 eV for Ge, ~0.05 eV for Si) is much less than the intrinsic band gap energy, so doping greatly increases free electron concentration independent of temperature.

In n-type semiconductors, the majority carriers are electrons (n_e >> n_h), and holes are minority carriers. The total conduction electron concentration includes both donor electrons and thermally generated intrinsic electrons, while holes come only from intrinsic generation. Recombination reduces hole concentration further.

In p-type semiconductors, trivalent dopants replace Si or Ge atoms but have one less valence electron, resulting in a vacancy or hole in the covalent bond. This hole acts as a positive charge carrier. The dopant atom becomes negatively charged after accepting an electron from a neighboring atom. These dopants are called acceptor impurities. The holes generated by doping are majority carriers (n_h >> n_e), while electrons are minority carriers. The acceptor energy level lies slightly above the valence band, allowing electrons to jump into it with small energy, creating holes in the valence band.

The product of electron and hole concentrations in thermal equilibrium satisfies the relation:

n_e × n_h = n_i²

Doping shifts the balance of carriers, increasing majority carriers and reducing minority carriers due to recombination.

Energy band diagrams for n-type and p-type semiconductors show donor and acceptor levels near conduction and valence bands respectively.

This section explains how doping controls semiconductor conductivity and carrier type, enabling practical electronic devices.

📊 Diagram: Figure 14.7(a) shows a pentavalent donor atom doped in Si or Ge lattice forming n-type semiconductor; (b) schematic representation showing fixed positive cores and extra electrons. Figure 14.8(a) shows a trivalent acceptor atom doped in Si or Ge lattice forming p-type semiconductor; (b) schematic representation showing fixed negative cores and associated holes. Figure 14.9(a) shows energy band diagram of n-type semiconductor with donor level near conduction band; (b) shows p-type with acceptor level near valence band.

🧪 Activity: No specific activity mentioned in this section.

🔗 Connection: Prepares for understanding p-n junction formation and behavior.

Frequently asked questions

In an n-type silicon, which of the following statement is true: (a) Electrons are majority carriers and trivalent atoms are the dopants. (b) Electrons are minority carriers and pentavalent atoms are the dopants. (c) Holes are minority carriers and pentavalent atoms are the dopants. (d) Holes are majority carriers and trivalent atoms are the dopants.

Option (c) is correct: Holes are minority carriers and pentavalent atoms are the dopants in n-type silicon.

Explanation: In n-type silicon, pentavalent atoms (such as phosphorus, arsenic) are added as dopants. These atoms have five valence electrons, one more than silicon's four valence electrons. The extra electron becomes a free electron, making electrons the majority carriers. Holes, which are the absence of electrons, are minority carriers in n-type silicon.

Therefore, electrons are majori

Carbon, silicon and germanium have four valence electrons each. These are characterised by valence and conduction bands separated by energy band gap respectively equal to $(E_{ ext{g}})_{ ext{C}}$, $(E_{ ext{g}})_{ ext{Si}}$ and $(E_{ ext{g}})_{ ext{Ge}}$. Which of the following statements is true? (a) $(E_{ ext{g}})_{ ext{Si}} < (E_{ ext{g}})_{ ext{Ge}} < (E_{ ext{g}})_{ ext{C}}$ (b) $(E_{ ext{g}})_{ ext{C}} < (E_{ ext{g}})_{ ext{Ge}} > (E_{ ext{g}})_{ ext{Si}}$ (c) $(E_{ ext{g}})_{ ext{C}} > (E_{ ext{g}})_{ ext{Si}} > (E_{ ext{g}})_{ ext{Ge}}$ (d) $(E_{ ext{g}})_{ ext{C}} = (E_{ ext{g}})_{ ext{Si}} = (E_{ ext{g}})_{ ext{Ge}}$

The correct statement is (a) $(E_{\mathrm{g}})_{\mathrm{Si}} < (E_{\mathrm{g}})_{\mathrm{Ge}} < (E_{\mathrm{g}})_{\mathrm{C}}$. Explanation: Carbon (diamond) has the largest band gap (~5.5 eV), silicon has an intermediate band gap (~1.1 eV), and germanium has the smallest band gap (~0.66 eV). Thus, the energy band gap decreases in the order Carbon > Silicon > Germanium.

In an unbiased p-n junction, holes diffuse from the p-region to n-region because (a) free electrons in the n-region attract them. (b) they move across the junction by the potential difference. (c) hole concentration in p-region is more as compared to n-region. (d) All the above.

The correct answer is (c) hole concentration in p-region is more as compared to n-region.

Explanation: In an unbiased p-n junction, diffusion occurs due to concentration gradient. Holes diffuse from the region of higher concentration (p-region) to the region of lower concentration (n-region). The movement is driven by concentration difference, not by attraction of free electrons or potential difference.

When a forward bias is applied to a p-n junction, it (a) raises the potential barrier. (b) reduces the majority carrier current to zero. (c) lowers the potential barrier. (d) None of the above.

The correct answer is (c) lowers the potential barrier.

Explanation: Applying a forward bias to a p-n junction reduces the built-in potential barrier, allowing majority carriers to cross the junction more easily, thus increasing current flow.

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