Redox Reactions: Complete Guide for Class 11 NCERT Chemistry
By ConceptScroll Team · Published on 2 July 2026 · 5 min read

Redox Reactions are chemical processes involving oxidation and reduction, essential for Class 11 NCERT Chemistry. This guide explains their types, mechanisms, and examples, helping students grasp this fundamental concept with clarity and confidence.
What Are Redox Reactions?
Redox Reactions are chemical reactions where oxidation and reduction occur simultaneously. Oxidation means loss of electrons, while reduction means gain of electrons. These reactions are fundamental in processes like combustion, corrosion, and cellular respiration.
In Class 11 NCERT Chemistry, understanding redox reactions helps explain how substances interact by exchanging electrons. The term "redox" is a combination of "reduction" and "oxidation". For example, in the reaction:
$$\text{Zn} + \text{CuSO}_4 \rightarrow \text{ZnSO}_4 + \text{Cu}$$
Zinc loses electrons (oxidised) and copper ions gain electrons (reduced). This electron transfer is the core of redox reactions.
Types of Redox Reactions Explained
Redox reactions are classified into four main types based on how substances react:
1. Combination Reactions: Two or more substances combine to form one product. At least one reactant is elemental.
- Example: $\text{C}(s) + \text{O}_2(g) \rightarrow \text{CO}_2(g)$
2. Decomposition Reactions: A compound breaks down into two or more substances, including at least one element.
- Example: $2\text{H}_2\text{O}(l) \rightarrow 2\text{H}_2(g) + \text{O}_2(g)$
3. Displacement Reactions: An element displaces another from its compound.
- Metal displacement: $\text{CuSO}_4(aq) + \text{Zn}(s) \rightarrow \text{Cu}(s) + \text{ZnSO}_4(aq)$
- Non-metal displacement: $\text{Cl}_2(g) + 2\text{KBr}(aq) \rightarrow 2\text{KCl}(aq) + \text{Br}_2(l)$
4. Disproportionation Reactions: A single element undergoes both oxidation and reduction.
- Example: $2\text{H}_2\text{O}_2(aq) \rightarrow 2\text{H}_2\text{O}(l) + \text{O}_2(g)$
Understanding these types helps in identifying and balancing redox reactions.
Want to test yourself on Redox Reactions? Try our free quiz →
Combination and Decomposition Reactions in Detail
Combination Reactions
In these reactions, two or more reactants form a single product. At least one reactant is in elemental form, which undergoes oxidation or reduction.
Examples:
- $3\text{Mg}(s) + \text{N}_2(g) \rightarrow \text{Mg}_3\text{N}_2(s)$
- $\text{CH}_4(g) + 2\text{O}_2(g) \rightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(l)$
These reactions are common in synthesis and combustion.
Decomposition Reactions
Here, a compound breaks down into simpler substances, at least one being elemental.
Examples:
- $2\text{NaH}(s) \rightarrow 2\text{Na}(s) + \text{H}_2(g)$
- $2\text{KClO}_3(s) \rightarrow 2\text{KCl}(s) + 3\text{O}_2(g)$
Note: Not all decomposition reactions are redox. For instance, the decomposition of calcium carbonate ($\text{CaCO}_3$) is not a redox reaction because oxidation states remain unchanged.
These reactions illustrate how redox processes can both build and break chemical bonds.
Displacement Reactions: Metal and Non-Metal Examples
Displacement reactions occur when an element displaces another from its compound. These are important in metal extraction and halogen chemistry.
Metal Displacement:
- A more reactive metal displaces a less reactive metal from its salt solution.
- Example:
$$\text{CuSO}_4(aq) + \text{Zn}(s) \rightarrow \text{Cu}(s) + \text{ZnSO}_4(aq)$$
- Other examples include:
- $\text{V}_2\text{O}_5(s) + 5\text{Ca}(s) \rightarrow 2\text{V}(s) + 5\text{CaO}(s)$
- $\text{Cr}_2\text{O}_3(s) + 2\text{Al}(s) \rightarrow \text{Al}_2\text{O}_3(s) + 2\text{Cr}(s)$
Non-Metal Displacement:
- Halogens displace other halide ions due to higher reactivity.
- Examples:
- $\text{Cl}_2(g) + 2\text{KBr}(aq) \rightarrow 2\text{KCl}(aq) + \text{Br}_2(l)$
- $\text{Cl}_2(g) + 2\text{KI}(aq) \rightarrow 2\text{KCl}(aq) + \text{I}_2(s)$
Hydrogen Displacement:
- Metals can displace hydrogen from water or acids.
- Examples:
- $2\text{Na}(s) + 2\text{H}_2\text{O}(l) \rightarrow 2\text{NaOH}(aq) + \text{H}_2(g)$
- $\text{Zn}(s) + 2\text{HCl}(aq) \rightarrow \text{ZnCl}_2(aq) + \text{H}_2(g)$
These reactions demonstrate electron transfer and reactivity trends in the periodic table.
Understanding Disproportionation Reactions
Disproportionation reactions are unique redox processes where a single element is simultaneously oxidised and reduced, producing two different products.
Key Examples:
- Hydrogen peroxide decomposition:
$$2\text{H}_2\text{O}_2(aq) \rightarrow 2\text{H}_2\text{O}(l) + \text{O}_2(g)$$ Here, oxygen in $\text{H}_2\text{O}_2$ is both oxidised to $\text{O}_2$ and reduced to $\text{H}_2\text{O}$.
- Chlorine in alkaline medium:
$$\text{Cl}_2(g) + 2\text{OH}^-(aq) \rightarrow \text{ClO}^-(aq) + \text{Cl}^-(aq) + \text{H}_2\text{O}(l)$$
- Phosphorus and sulfur disproportionation also occur in basic solutions forming multiple oxidation state products.
Important Note: Fluorine does not undergo disproportionation due to its high electronegativity and inability to form positive oxidation states.
Disproportionation reactions highlight the versatility of elements in redox chemistry.
Balancing Redox Reactions: The Basics
Balancing redox reactions is crucial for solving Class 11 NCERT problems. It ensures mass and charge conservation.
Steps to Balance Redox Reactions: 1. Write the unbalanced equation. 2. Separate into oxidation and reduction half-reactions. 3. Balance atoms other than O and H. 4. Balance oxygen atoms by adding $\text{H}_2\text{O}$. 5. Balance hydrogen atoms by adding $\text{H}^+$ (in acidic medium) or $\text{OH}^-$ (in basic medium). 6. Balance charges by adding electrons ($e^-$). 7. Equalize electrons in both half-reactions. 8. Add the half-reactions and simplify.
Example: Balance the reaction between permanganate ion and iron(II) ion in acidic medium:
Unbalanced: $$\text{MnO}_4^- + \text{Fe}^{2+} \rightarrow \text{Mn}^{2+} + \text{Fe}^{3+}$$
Oxidation half-reaction: $$\text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + e^-$$
Reduction half-reaction: $$\text{MnO}_4^- + 8\text{H}^+ + 5e^- \rightarrow \text{Mn}^{2+} + 4\text{H}_2\text{O}$$
Multiply oxidation half by 5 and add: $$5\text{Fe}^{2+} + \text{MnO}_4^- + 8\text{H}^+ \rightarrow 5\text{Fe}^{3+} + \text{Mn}^{2+} + 4\text{H}_2\text{O}$$
Balancing redox reactions is essential for chemical equations and electrochemistry topics.
Comparison Table: Types of Redox Reactions
| Type | Description | Example Reaction |
|---|---|---|
| Combination | Two or more substances form one product | $\text{C} + \text{O}_2 \rightarrow \text{CO}_2$ |
| Decomposition | Compound breaks into simpler substances | $2\text{H}_2\text{O} \rightarrow 2\text{H}_2 + \text{O}_2$ |
| Displacement (Metal) | Metal displaces another metal from compound | $\text{CuSO}_4 + \text{Zn} \rightarrow \text{Cu} + \text{ZnSO}_4$ |
| Displacement (Non-metal) | Halogen displaces another halide ion | $\text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2$ |
| Disproportionation | One element oxidised and reduced simultaneously | $2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2$ |
Frequently asked questions
What is a redox reaction in Class 11 Chemistry?
A redox reaction involves simultaneous oxidation and reduction where electrons are transferred between substances.
How many types of redox reactions are there?
There are four main types: Combination, Decomposition, Displacement, and Disproportionation reactions.
Can you give an example of a displacement reaction?
Yes, zinc displacing copper from copper sulfate: Zn + CuSO4 → Cu + ZnSO4.
Why does fluorine not show disproportionation reactions?
Fluorine's high electronegativity prevents it from having positive oxidation states, so it does not disproportionate.
How do you balance redox reactions in acidic medium?
Balance atoms except O and H, then add H2O for oxygen, H+ for hydrogen, and electrons to balance charge.
Ready to ace this chapter?
Get the full Redox Reactions chapter — interactive notes, diagrams, worked solutions, polls and a free practice quiz — in the ConceptScroll app.
Study smarter with ConceptScroll
Daily NCERT-aligned reels, AI doubt solving and chapter quizzes — all free.
Start learning freeContinue reading
- Equilibrium in Chemistry: Understanding Class 11 NCERT Concepts
This blog explains the concept of equilibrium in chemistry as per Class 11 NCERT syllabus. Understand dynamic equilibrium, equilibrium constant, and related principles with examples.
- Equilibrium in Chemistry: Complete Guide for Class 11 NCERT Students
Understand equilibrium in Chemistry for Class 11 NCERT students. Learn about physical and chemical equilibrium, dynamic balance, and important formulas with examples.
- Equilibrium in Chemistry: Complete Guide for Class 11 NCERT Students
Explore the concept of equilibrium in Class 11 NCERT Chemistry. Learn its dynamic nature, laws, and factors affecting chemical and physical equilibria.