Quadratic Equations | Class 10 Mathematics Notes
By ConceptScroll Team · Published on 17 July 2026 · 2 min read

Quadratic Equations – this guide gives you a concise, exam-ready overview of Quadratic Equations from Class 10 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.
4.3 Solution of a Quadratic Equation by Factorisation
This section explains how to find the roots (solutions) of a quadratic equation by factorisation. A root α of the quadratic equation ax² + bx + c = 0 is a real number such that aα² + bα + c = 0. The roots of the quadratic equation correspond to the zeroes of the quadratic polynomial ax² + bx + c.
Since a quadratic polynomial can have at most two zeroes, a quadratic equation can have at most two roots. The method of factorisation involves expressing the quadratic polynomial as a product of two linear factors and then setting each factor equal to zero to find the roots.
The section provides detailed examples illustrating this method:
- Example 3: Solve 2x² - 5x + 3 = 0 by splitting the middle term -5x into -2x and -3x, factorising as (2x - 3)(x - 1) = 0, giving roots x = 3/2 and x = 1.
- Example 4: Solve 6x² - x - 2 = 0 by splitting -x into 3x and -4x, factorising as (3x - 2)(2x + 1) = 0, giving roots x = 2/3 and x = -1/2.
- Example 5: Solve 3x² - 2√6 x + 2 = 0 by expressing as (√3 x - √2)² = 0, giving a repeated root x = √(2/3).
- Example 6: Apply factorisation to the prayer hall problem's quadratic equation 2x² + x - 300 = 0, factorising as (x - 12)(2x + 25) = 0, discarding the negative root, and concluding the breadth is 12 m and length 25 m.
The section emphasizes verifying roots by substituting back into the original equation and highlights that factorisation is a powerful method when applicable.
📊 Diagram: Fig. 4.1
🧪 Activity: Example 3-6 illustrate factorisation method for solving quadratic equations.
🔗 Connection: After learning factorisation, the next section discusses the nature of roots using the discriminant.
Frequently asked questions
The pair of equations y=0 and y=-7 has
No solutions
The given system of equations 6x+5y =4 and 12x+ky =8 has infinitely many solutions , then the value of k is
10
If the equation x 2 – Px + 1 = 0 possess equal real roots, then ;
P= +,- 2
MCQ (5) 2x^2+5x+5=0 ಸಮೀಕರಣದ ಮೂಲಗಳ ಸ್ವಭಾವ
ಯಾವುದೇ ವಾಸ್ತವ ಮೂಲಗಳಿಲ್ಲ
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