MathematicsClass 11Permutations and Combinations

Permutations and Combinations | Class 11 Mathematics Notes

By ConceptScroll Team · Published on 17 July 2026 · 3 min read

Permutations and Combinations | Class 11 Mathematics Notes

Permutations and Combinations – this guide gives you a concise, exam-ready overview of Permutations and Combinations from Class 11 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.

6.2 Fundamental Principle of Counting

This section introduces the Fundamental Principle of Counting, also known as the multiplication principle. It states that if one event can occur in m ways and a subsequent event can occur in n ways, then the total number of ways both events can occur in sequence is m × n. This principle generalizes to any finite number of successive events, where the total number of outcomes is the product of the number of ways each event can occur. Two illustrative problems are presented: Mohan choosing pants and shirts, and Sabnam choosing school bags, tiffin boxes, and water bottles. The section explains how to count the total number of possible pairs or triplets by multiplying the number of choices at each step. Several examples demonstrate the application of this principle to counting arrangements of letters, flags, and digits with or without repetition. The principle is fundamental to understanding permutations and combinations, as it provides a systematic way to count complex arrangements by breaking them down into simpler successive choices.

📊 Diagram: Fig 6.1; Fig 6.2

🧪 Activity: No specific activity, but examples illustrate the principle.

🔗 Connection: Prepares for formal introduction of permutations, which count ordered arrangements.

Frequently asked questions

1. How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed?

(i) When repetition of digits is allowed, each of the 3 places can be filled with any of the 5 digits. So, number of 3-digit numbers = 5 × 5 × 5 = 125.

(ii) When repetition is not allowed, the first digit can be chosen in 5 ways, the second in 4 ways (excluding the first digit), and the third in 3 ways. So, number of 3-digit numbers = 5 × 4 × 3 = 60.

2. How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

To form a 3-digit even number, the last digit must be even. Digits available: 1,2,3,4,5,6 Even digits: 2,4,6 (3 choices for last digit) Since repetition is allowed: First digit: 6 choices (1 to 6) Second digit: 6 choices (1 to 6) Third digit (last digit): 3 choices (2,4,6) Total numbers = 6 × 6 × 3 = 108.

3. How many 4-letter code can be formed using the first 10 letters of the English alphabet, if no letter can be repeated?

First 10 letters: A, B, C, D, E, F, G, H, I, J No repetition allowed. Number of 4-letter codes = Number of permutations of 10 letters taken 4 at a time = {}^{10}P_4 = 10 × 9 × 8 × 7 = 5040.

4. How many 5-digit telephone numbers can be constructed using the digits 0 to 9 if each number starts with 67 and no digit appears more than once?

The telephone number is 5-digit starting with 6 and 7. Digits used: 0 to 9 First two digits fixed: 6 and 7 Remaining 3 digits to be chosen from digits excluding 6 and 7 (digits left = 8) No repetition allowed. Number of ways = permutations of 8 digits taken 3 at a time = {}^{8}P_3 = 8 × 7 × 6 = 336.

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