Number Play | Class 8 Mathematics Notes
By ConceptScroll Team · Published on 17 July 2026 · 4 min read

Number Play – this guide gives you a concise, exam-ready overview of Number Play from Class 8 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.
Is This a Multiple Of?
This section introduces the exploration of sums of consecutive numbers and their properties. Anshu's observations about expressing numbers as sums of consecutive natural numbers spark several intriguing questions: Can every natural number be written as a sum of consecutive numbers? Which numbers can be expressed in more than one way as such sums? Are all odd numbers expressible as sums of two consecutive numbers? Can all even numbers be expressed as sums of consecutive numbers? Can zero be expressed as a sum of consecutive numbers, possibly involving negative numbers? These questions encourage students to investigate patterns and properties of numbers through experimentation and reasoning.
The section further explores the parity (evenness or oddness) of expressions formed by placing '+' and '−' signs between four consecutive numbers. By systematically listing all eight possible expressions formed by four consecutive numbers and evaluating their sums, students observe that the results always have the same parity — specifically, they are always even numbers. This observation is generalized using algebraic reasoning, showing that switching signs changes the sum by an even number, thus preserving parity. The parity rules for sums and differences of odd and even numbers are revisited to support this conclusion.
The section also hints at alternative explanations using positive and negative token models and encourages students to ponder whether this parity phenomenon holds for any set of four numbers, not just consecutive ones. This inquiry nurtures mathematical curiosity and introduces the power of algebraic reasoning to prove general properties without exhaustive computation.
📊 Diagram: See figure_1: ? Evaluate each expression and write the result next to it. Do you notice anything interesting?; See figure_2, figure_3, figure_4: Some sums appear always no matter which 4 consecutive numbers are chosen. Isn't that interesting?
🧪 Activity: Students are encouraged to take any four consecutive numbers, place '+' and '−' signs in all possible ways, evaluate each expression, and observe the parity of results. They are also guided to use algebraic expressions to reason about these observations.
🔗 Connection: This section lays the foundation for understanding parity and divisibility properties, leading into the next section 'Breaking Even', which explores identifying even numbers in arithmetic expressions and algebraic forms.
Frequently asked questions
6. If 3p7q8 is divisible by 44, list all possible pairs of values for p and q.
3p7q8 is divisible by 44, means divisible by 11 and 4. For divisibility by 4, last two digits must be divisible by 4. So possible q8 are 08, 28, 48, 68, 88. For divisibility by 11, difference between sum of the odd place digits and even place digits must be 0 or multiple of 11. Sum of odd place digits = 8 + 7 + 3 = 18. Sum of even place digits = p + q. Difference is 18 − (p + q). Let k = 18 − (p + q) = 0 or a multiple of 11. (i) if p + q = 18 Not possible for q (0, 2, 4, 6, 8), since p is a digi
7. Find three consecutive numbers such that the first number is a multiple of 2, the second number is a multiple of 3, and the third number is a multiple of 4. Are there more such numbers? How often do they occur?
Let the three consecutive numbers be n, n+1, n+2. Given: n is multiple of 2, n+1 is multiple of 3, n+2 is multiple of 4. One such set is 2, 3, 4. Since the numbers are consecutive, the pattern repeats every LCM of 2, 3, and 4, which is 12. So, the next such set is 14, 15, 16. Hence, such numbers occur every 12 numbers.
8. Write five multiples of 36 between 45,000 and 47,000. Share your approach with the class.
Since 36 = 4 × 9, a number divisible by 36 must be divisible by both 4 and 9. For divisibility by 4, last two digits must be divisible by 4. For divisibility by 9, sum of digits must be divisible by 9. Between 45000 and 47000, multiples of 36 are: 45036, 45072, 45108, 45144, 45180. Approach: Check numbers ending with last two digits divisible by 4 and sum of digits divisible by 9.
9. The middle number in the sequence of 5 consecutive even numbers is 5p. Express the other four numbers in sequence in terms of p.
Let the five consecutive even numbers be: 5p - 4, 5p - 2, 5p, 5p + 2, 5p + 4. Since the middle number is 5p, the two numbers before it are 2 and 4 less, and the two numbers after it are 2 and 4 more, respectively.
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