Introduction to | Class 9 Mathematics Notes
By ConceptScroll Team · Published on 17 July 2026 · 5 min read

Introduction to – this guide gives you a concise, exam-ready overview of Introduction to from Class 9 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.
2.2 LINEAR POLYNOMIALS
This section focuses on linear polynomials, which are polynomials of degree one. It begins with examples illustrating linear polynomials in real-life contexts. For example, the perimeter of a square with side length x is 4x, a linear polynomial. Another example involves a chess club charging a fixed joining fee plus a variable fee per match played, expressed as 200 + 50m, where m is the number of matches.
The section highlights a key feature of linear polynomials: the difference between successive values at integer inputs is constant. This characteristic defines linear patterns, where quantities increase or decrease by a fixed amount over equal intervals.
The section also introduces the concept of linear equations formed by equating a linear polynomial to a constant, demonstrated through a problem involving two numbers whose sum and difference are given.
Further, it presents the idea of polynomials as functions or input-output processes. For instance, the linear polynomial 2x + 3 can be viewed as a function where substituting values for x yields corresponding outputs. This concept is visualized through an input-output machine diagram.
The section contrasts linear functions with quadratic functions, emphasizing the degree and nature of the polynomial. Exercises encourage evaluating linear and quadratic polynomials at various values and solving real-life problems using linear polynomials.
📊 Diagram: Fig. 2.3 illustrates a linear expression 2x + 3 as an input-output process, showing substitution of values for x and corresponding outputs.
🧪 Activity: Think and Reflect questions prompt students to evaluate polynomials at given values and interpret algebraic expressions as functions.
🔗 Connection: This section sets the foundation for exploring linear patterns and relationships in the next section.
Frequently asked questions
1. Suppose a plant has height 1.75 feet and it grows by 0.5 feet each month. (i) Find the height after 7 months. (ii) Make a table of values for $t$ varying from 0 to 10 months and show how the height, $h$, increases every month. (iii) Find an expression that relates $h$ and $t$, and explain why it represents linear growth.
(i) Initial height = 1.75 feet, growth per month = 0.5 feet Height after 7 months = Initial height + 7 × growth per month = 1.75 + 7 × 0.5 = 1.75 + 3.5 = 5.25 feet
(ii) Table of values:
| t (months) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|---|---|---|---|---|---|---|---|---|---|---|---|
| h (feet) | 1.75 | 2.25 | 2.75 | 3.25 | 3.75 | 4.25 | 4.75 | 5.25 | 5.75 | 6.25 | 6.75 |
(iii) Expression relating height h and time t:
h = 1.75 + 0.5t
This is a linear expression because h changes by a consta
2. A mobile phone is bought for ₹10,000. Its value decreases by ₹800 every year. (i) Find the value of the phone after 3 years. (ii) Make a table of values for $t$ varying from 0 to 8 years and show how the value of the phone, $\nu$, depreciates with time. (iii) Find an expression that relates $\nu$ and $t$, and explain why it represents linear decay.
(i) Initial value = ₹10,000 Depreciation per year = ₹800 Value after 3 years = Initial value - 3 × depreciation = 10000 - 3 × 800 = 10000 - 2400 = ₹7600
(ii) Table of values:
| t (years) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
|---|---|---|---|---|---|---|---|---|---|
| ν (₹) | 10000 | 9200 | 8400 | 7600 | 6800 | 6000 | 5200 | 4400 | 3600 |
(iii) Expression relating value ν and time t:
ν = 10000 - 800t
This represents linear decay because the value decreases by a fixed amount (₹800) every y
3. The initial population of a village is 750. Every year, 50 people move from a nearby city to the village. (i) Find the population of the village after 6 years. (ii) Make a table of values for $t$ varying from 0 to 10 years and show how the population, $P$, increases every year. (iii) Find an expression that relates $P$ and $t$, and explain why it represents linear growth.
(i) Initial population = 750 Increase per year = 50 Population after 6 years = 750 + 6 × 50 = 750 + 300 = 1050
(ii) Table of values:
| t (years) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|---|---|---|---|---|---|---|---|---|---|---|---|
| P | 750 | 800 | 850 | 900 | 950 | 1000 | 1050 | 1100 | 1150 | 1200 | 1250 |
(iii) Expression relating population P and time t:
P = 750 + 50t
This represents linear growth because the population increases by a fixed number (50) every year. The
4. A telecom company charges ₹600 for a certain recharge scheme. This prepaid balance is reduced by ₹15 each day after the recharge. (i) Write an equation that models the remaining balance $b(x)$ after using the scheme for $x$ days. Explain why it represents linear decay. (ii) After how many days will the balance run out? (iii) Make a table of values for $x$ varying from 1 to 10 days and show how the balance $b(x)$, reduces with time.
(i) Initial balance = ₹600 Daily reduction = ₹15 Equation for balance after x days:
b(x) = 600 - 15x
This represents linear decay because the balance decreases by a fixed amount (₹15) each day.
(ii) To find when balance runs out, set b(x) = 0:
0 = 600 - 15x 15x = 600 x = 600 / 15 = 40 days
(iii) Table of values:
| x (days) | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|---|---|---|---|---|---|---|---|---|---|---|
| b(x) (₹) | 585 | 570 | 555 | 540 | 525 | 510 | 495 | 480 | 465 | 450 |
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