5.1 Introduction | Class 8 Mathematics Notes
By ConceptScroll Team · Published on 17 July 2026 · 5 min read

5.1 Introduction – this guide gives you a concise, exam-ready overview of 5.1 Introduction from Class 8 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.
5.3 Some More Interesting Patterns
This section delves into fascinating numerical patterns involving square numbers, triangular numbers, odd numbers, and products of consecutive numbers.
1. Adding Triangular Numbers: The section recalls triangular numbers, which can be arranged in dot patterns forming triangles. It shows that the sum of two consecutive triangular numbers results in a perfect square. For example, 1 + 3 = 4 = 2², 3 + 6 = 9 = 3², and 6 + 10 = 16 = 4². This illustrates a beautiful connection between triangular and square numbers.
2. Numbers Between Square Numbers: The section examines the count of natural numbers lying between consecutive square numbers. It observes that between n² and (n+1)², there are 2n non-square numbers. For instance, between 1²=1 and 2²=4, there are 2 numbers (2 and 3); between 2²=4 and 3²=9, there are 4 numbers (5, 6, 7, 8). The difference between consecutive squares is given by (n+1)² - n² = 2n + 1.
3. Adding Odd Numbers: It is shown that the sum of the first n odd natural numbers equals n². For example, 1 = 1², 1 + 3 = 4 = 2², 1 + 3 + 5 = 9 = 3², and so on. This property is used to determine whether a number is a perfect square by trying to express it as a sum of successive odd numbers starting from 1.
4. Sum of Two Consecutive Natural Numbers: The section notes that some square numbers can be expressed as the sum of two consecutive natural numbers. For example, 9² = 81 = 40 + 41, 11² = 121 = 60 + 61.
5. Product of Two Consecutive Even or Odd Numbers: It is observed that the product of two consecutive odd or even numbers can be expressed as a difference of squares: (a + 1)(a - 1) = a² - 1. Examples include 11 × 13 = 12² - 1 = 143.
6. More Patterns in Square Numbers: The section presents intriguing patterns in the squares of numbers like 1, 11, 111, etc., and numbers like 7, 67, 667, showing symmetrical digit patterns in their squares, inviting students to explore these further.
The section includes exercises encouraging students to identify and extend these patterns.
📊 Diagram: Dot patterns showing triangular numbers and their sums forming squares; Table showing numbers between squares; Tables illustrating sums of odd numbers and products of consecutive numbers; See figure_12, figure_13, figure_14, figure_15, figure_16.
🧪 Activity: Students are encouraged to find the number of natural numbers between given squares, express numbers as sums of odd numbers, and identify patterns in squares.
🔗 Connection: This section sets the stage for the next section, which explains methods to find the square of a number efficiently.
Frequently asked questions
1. What will be the unit digit of the squares of the following numbers? (i) 81 (ii) 272 (iii) 799 (iv) 3853 (v) 1234 (vi) 26387 (vii) 52698 (viii) 99880 (ix) 12796 (x) 55555
To find the unit digit of the square of a number, we only need to consider the unit digit of the number itself and then find the unit digit of its square.
(i) 81 ends with 1; 1^2 = 1 → unit digit 1 (ii) 272 ends with 2; 2^2 = 4 → unit digit 4 (iii) 799 ends with 9; 9^2 = 81 → unit digit 1 (iv) 3853 ends with 3; 3^2 = 9 → unit digit 9 (v) 1234 ends with 4; 4^2 = 16 → unit digit 6 (vi) 26387 ends with 7; 7^2 = 49 → unit digit 9 (vii) 52698 ends with 8; 8^2 = 64 → unit digit 4 (viii) 99880 ends wi
2. The following numbers are obviously not perfect squares. Give reason. (i) 1057 (ii) 23453 (iii) 7928 (iv) 222222 (v) 64000 (vi) 89722 (vii) 222000 (viii) 505050
A number is a perfect square only if its unit digit is 0,1,4,5,6 or 9. Also, perfect squares have specific patterns.
(i) 1057 ends with 7; 7^2 ends with 9 or 3, so 1057 cannot be a perfect square. (ii) 23453 ends with 3; no perfect square ends with 3. (iii) 7928 ends with 8; no perfect square ends with 8. (iv) 222222 ends with 2; no perfect square ends with 2. (v) 64000 ends with 0 but the number of zeros is not even (perfect squares ending with 0 have even number of zeros), so not a perfect sq
3. The squares of which of the following would be odd numbers? (i) 431 (ii) 2826 (iii) 7779 (iv) 82004
Squares of odd numbers are odd; squares of even numbers are even.
(i) 431 is odd → square is odd (ii) 2826 is even → square is even (iii) 7779 is odd → square is odd (iv) 82004 is even → square is even
4. Observe the following pattern and find the missing digits. 11^2 = 121 101^2 = 10201 1001^2 = 1002001 100001^2 = 1 ... 2 ... 1 10000001^2 = ...
The pattern shows that:
11^2 = 121 101^2 = 10201 1001^2 = 1002001
Notice the pattern: For 1 followed by n zeros and 1, the square is 1 followed by n-1 zeros, then 2, then n-1 zeros, then 1.
For 100001^2 (which is 1 followed by 4 zeros and 1):
Square = 1 0000 2 0000 1 = 10000200001
For 10000001^2 (1 followed by 6 zeros and 1):
Square = 1 000000 2 000000 1 = 100000020000001
Ready to ace this chapter?
Get the full 5.1 Introduction chapter — interactive notes, diagrams, worked solutions, polls and a free practice quiz — in the ConceptScroll app.
Study smarter with ConceptScroll
Daily NCERT-aligned reels, AI doubt solving and chapter quizzes — all free.
Start learning freeContinue reading
- Introduction to Graphs | Class 8 Mathematics Notes
Clear NCERT-aligned notes on Introduction to Graphs for Class 8 Mathematics.
- Introduction to Graphs | Class 8 Mathematics Notes
Clear NCERT-aligned notes on Introduction to Graphs for Class 8 Mathematics.
- Introduction to Graphs | Class 8 Mathematics Notes
Clear NCERT-aligned notes on Introduction to Graphs for Class 8 Mathematics.