MathematicsClass 85.1 Introduction

5.1 Introduction | Class 8 Mathematics Notes

By ConceptScroll Team · Published on 17 July 2026 · 5 min read

5.1 Introduction | Class 8 Mathematics Notes

5.1 Introduction – this guide gives you a concise, exam-ready overview of 5.1 Introduction from Class 8 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.

5.5 Square Roots

This section introduces the concept of square roots as the inverse operation of squaring. It begins with real-life situations where finding the side of a square or the length of a triangle side requires determining a number whose square is known.

The square root of a number is defined as the number which, when multiplied by itself, gives the original number. For example, since 3² = 9, the square root of 9 is 3. The section notes that every perfect square has two integral square roots: one positive and one negative (e.g., 9 and -9 are square roots of 81). However, for the purpose of this chapter, only the positive square root is considered and denoted by the symbol √.

The section presents a table showing numbers from 1 to 10 and their squares, along with the corresponding square roots.

It then explains the method of finding square roots through repeated subtraction of successive odd numbers starting from 1. For example, subtracting 1, 3, 5, 7, 9, ... from 25 successively results in zero at the fifth step, indicating that 25 is a perfect square and its square root is 5.

Next, the section introduces finding square roots through prime factorisation. It explains that the prime factors of a square number occur in pairs. By pairing the prime factors of a number, the square root can be found as the product of one factor from each pair. Examples include finding the square root of 324 and 256.

The section also discusses how to determine if a number is a perfect square by checking if all prime factors occur in pairs. If not, multiplying by the missing factors can yield a perfect square.

Finally, the section introduces the long division method for finding square roots of large numbers. It explains how to estimate the number of digits in the square root based on the number of digits in the square and demonstrates the step-by-step procedure with examples.

Exercises encourage students to practice finding square roots using repeated subtraction, prime factorisation, and the division method.

📊 Diagram: Figures illustrating the concept of square roots in squares and right triangles (Fig 5.1 and Fig 5.2); Tables showing prime factorisation; Stepwise long division method for √529 and √4096; See figure_20, figure_21, figure_22, figure_23, figure_24, figure_25.

🧪 Activity: Students practice finding square roots by repeated subtraction, prime factorisation, and long division methods.

🔗 Connection: This section connects to the next, which covers square roots of decimal numbers and further applications.

Frequently asked questions

1. What will be the unit digit of the squares of the following numbers? (i) 81 (ii) 272 (iii) 799 (iv) 3853 (v) 1234 (vi) 26387 (vii) 52698 (viii) 99880 (ix) 12796 (x) 55555

To find the unit digit of the square of a number, we only need to consider the unit digit of the number itself and then find the unit digit of its square.

(i) 81 ends with 1; 1^2 = 1 → unit digit 1 (ii) 272 ends with 2; 2^2 = 4 → unit digit 4 (iii) 799 ends with 9; 9^2 = 81 → unit digit 1 (iv) 3853 ends with 3; 3^2 = 9 → unit digit 9 (v) 1234 ends with 4; 4^2 = 16 → unit digit 6 (vi) 26387 ends with 7; 7^2 = 49 → unit digit 9 (vii) 52698 ends with 8; 8^2 = 64 → unit digit 4 (viii) 99880 ends wi

2. The following numbers are obviously not perfect squares. Give reason. (i) 1057 (ii) 23453 (iii) 7928 (iv) 222222 (v) 64000 (vi) 89722 (vii) 222000 (viii) 505050

A number is a perfect square only if its unit digit is 0,1,4,5,6 or 9. Also, perfect squares have specific patterns.

(i) 1057 ends with 7; 7^2 ends with 9 or 3, so 1057 cannot be a perfect square. (ii) 23453 ends with 3; no perfect square ends with 3. (iii) 7928 ends with 8; no perfect square ends with 8. (iv) 222222 ends with 2; no perfect square ends with 2. (v) 64000 ends with 0 but the number of zeros is not even (perfect squares ending with 0 have even number of zeros), so not a perfect sq

3. The squares of which of the following would be odd numbers? (i) 431 (ii) 2826 (iii) 7779 (iv) 82004

Squares of odd numbers are odd; squares of even numbers are even.

(i) 431 is odd → square is odd (ii) 2826 is even → square is even (iii) 7779 is odd → square is odd (iv) 82004 is even → square is even

4. Observe the following pattern and find the missing digits. 11^2 = 121 101^2 = 10201 1001^2 = 1002001 100001^2 = 1 ... 2 ... 1 10000001^2 = ...

The pattern shows that:

11^2 = 121 101^2 = 10201 1001^2 = 1002001

Notice the pattern: For 1 followed by n zeros and 1, the square is 1 followed by n-1 zeros, then 2, then n-1 zeros, then 1.

For 100001^2 (which is 1 followed by 4 zeros and 1):

Square = 1 0000 2 0000 1 = 10000200001

For 10000001^2 (1 followed by 6 zeros and 1):

Square = 1 000000 2 000000 1 = 100000020000001

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