5.1 Introduction | Class 8 Mathematics Notes
By ConceptScroll Team · Published on 17 July 2026 · 4 min read

5.1 Introduction – this guide gives you a concise, exam-ready overview of 5.1 Introduction from Class 8 Mathematics, written by ConceptScroll editors and reviewed against the latest NCERT textbook.
5.2 Properties of Square Numbers
This section explores the properties and patterns of square numbers, focusing on the units digit and the distribution of square numbers among natural numbers. It begins with a table showing squares of numbers from 1 to 20, highlighting the units digit of each square number. It is observed that square numbers end only with digits 0, 1, 4, 5, 6, or 9. No square number ends with 2, 3, 7, or 8 in the units place.
The section cautions against assuming that any number ending with 0, 1, 4, 5, 6, or 9 is necessarily a square number, encouraging students to think critically about this.
Further, the section presents a detailed table (Table 1) of numbers and their squares, showing patterns such as which numbers produce squares ending in 1 or 6. For example, numbers ending with 1 or 9 produce squares ending with 1, and numbers ending with 4 or 6 produce squares ending with 6.
The section also discusses the relationship between the number of zeros at the end of a number and its square, noting that if a number ends with three zeros, its square ends with six zeros, implying that square numbers have an even number of zeros at the end.
Finally, the section distinguishes between squares of even and odd numbers, noting that the square of an even number is even, and the square of an odd number is odd.
Several exercises encourage students to apply these observations to determine whether given numbers are perfect squares based on their units digit and other properties.
📊 Diagram: Tables showing squares of numbers from 1 to 20, and Table 1 listing numbers and their squares with focus on units digit patterns; See figure_3, figure_4, figure_5, figure_6, figure_7, figure_8, figure_9, figure_10, figure_11.
🧪 Activity: Students are asked to determine if given numbers are perfect squares by observing their units digit and to write numbers that cannot be perfect squares based on this property.
🔗 Connection: This section prepares students for the next section, which explores interesting numerical patterns related to square numbers.
Frequently asked questions
1. What will be the unit digit of the squares of the following numbers? (i) 81 (ii) 272 (iii) 799 (iv) 3853 (v) 1234 (vi) 26387 (vii) 52698 (viii) 99880 (ix) 12796 (x) 55555
To find the unit digit of the square of a number, we only need to consider the unit digit of the number itself and then find the unit digit of its square.
(i) 81 ends with 1; 1^2 = 1 → unit digit 1 (ii) 272 ends with 2; 2^2 = 4 → unit digit 4 (iii) 799 ends with 9; 9^2 = 81 → unit digit 1 (iv) 3853 ends with 3; 3^2 = 9 → unit digit 9 (v) 1234 ends with 4; 4^2 = 16 → unit digit 6 (vi) 26387 ends with 7; 7^2 = 49 → unit digit 9 (vii) 52698 ends with 8; 8^2 = 64 → unit digit 4 (viii) 99880 ends wi
2. The following numbers are obviously not perfect squares. Give reason. (i) 1057 (ii) 23453 (iii) 7928 (iv) 222222 (v) 64000 (vi) 89722 (vii) 222000 (viii) 505050
A number is a perfect square only if its unit digit is 0,1,4,5,6 or 9. Also, perfect squares have specific patterns.
(i) 1057 ends with 7; 7^2 ends with 9 or 3, so 1057 cannot be a perfect square. (ii) 23453 ends with 3; no perfect square ends with 3. (iii) 7928 ends with 8; no perfect square ends with 8. (iv) 222222 ends with 2; no perfect square ends with 2. (v) 64000 ends with 0 but the number of zeros is not even (perfect squares ending with 0 have even number of zeros), so not a perfect sq
3. The squares of which of the following would be odd numbers? (i) 431 (ii) 2826 (iii) 7779 (iv) 82004
Squares of odd numbers are odd; squares of even numbers are even.
(i) 431 is odd → square is odd (ii) 2826 is even → square is even (iii) 7779 is odd → square is odd (iv) 82004 is even → square is even
4. Observe the following pattern and find the missing digits. 11^2 = 121 101^2 = 10201 1001^2 = 1002001 100001^2 = 1 ... 2 ... 1 10000001^2 = ...
The pattern shows that:
11^2 = 121 101^2 = 10201 1001^2 = 1002001
Notice the pattern: For 1 followed by n zeros and 1, the square is 1 followed by n-1 zeros, then 2, then n-1 zeros, then 1.
For 100001^2 (which is 1 followed by 4 zeros and 1):
Square = 1 0000 2 0000 1 = 10000200001
For 10000001^2 (1 followed by 6 zeros and 1):
Square = 1 000000 2 000000 1 = 100000020000001
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