Geometric
Geometric — Study Notes
NCERT-aligned · 4 notes · 3 shown free
1.1 Geometric Twins
Concept1.1 Geometric Twins
This section introduces the concept of congruence through the example of recreating a symbol seen on a signboard. The problem posed is how to exactly recreate the symbol on another board. One method is tracing the outline on tracing paper, but this is impractical for large symbols. The alternative is to take measurements that allow exact reconstruction. The symbol's corner points are named (e.g., points A, B, C), and the question arises whether knowing just the arm lengths AB and BC is sufficient to recreate the figure exactly. It is observed that multiple different shapes can be formed with the same two arm lengths, so these lengths alone do not guarantee an exact replica. To fix the shape and size, the measure of the angle between the arms, ∠ABC, is also needed along with the two arm lengths. With AB = 4 cm, BC = 8 cm, and ∠ABC = 80°, the symbol can be exactly drawn. Figures that are exact copies of each other, having the same shape and size, are called congruent figures. Congruent figures can be superimposed exactly, one over the other. The section explains that while checking congruence, figures may be rotated or flipped before superimposing. Several pairs of congruent figures are shown to illustrate this. It is emphasized that having the same arm lengths alone does not guarantee congruence; the angle between them must also be the same. This section ends with exercises to identify congruent figures and to consider what measurements are needed to create congruent circles and rectangles.
- Tracing is one way to replicate a figure but impractical for large symbols.
- Two arm lengths alone do not fix a figure's shape and size uniquely.
- Including the angle between the arms fixes the figure exactly.
- Figures with the same shape and size are congruent.
- Congruent figures can be superimposed exactly, possibly after rotation or flipping.
- Congruence requires corresponding sides and angles to be equal.
- 📌 Congruent figures: Figures that have the same shape and size and can be exactly superimposed.
- 📌 Angle between arms: The angle formed at the vertex connecting two sides.
1.2 Congruence of Triangles
Concept1.2 Congruence of Triangles
This section explores how to determine if two triangles are congruent and how to replicate a triangular frame exactly. Meera and Rabia want to make a cardboard cutout identical to a large triangular frame but cannot trace it directly. They measure the sides: 40 cm, 60 cm, and 80 cm. Meera suggests that side lengths alone are sufficient to construct a congruent triangle, without measuring angles. This is justified by the SSS (Side Side Side) condition: if two triangles have the same three side lengths, they are congruent. An example with smaller lengths (4 cm, 6 cm, 8 cm) is given. Rabia attempts construction by drawing one side and circles with radii equal to the other two sides from each endpoint, resulting in two possible triangles (ABE and ABF). These two triangles are congruent, as can be verified by tracing or symmetry arguments. The section explains conventions to express congruence, emphasizing the importance of matching corresponding vertices so that equal sides overlap when superimposed. The notation ΔABC ≅ ΔXYZ means vertex A corresponds to X, B to Y, and C to Z. Incorrect vertex order can lead to wrong conclusions. Examples with rectangles and other triangles illustrate correct vertex correspondence. The section also discusses measuring angles alone is insufficient for congruence, as triangles with equal angles can differ in size (similar triangles). The SAS (Side Angle Side) condition is introduced: two sides and the included angle equal in two triangles guarantee congruence. The SSA (Side Side Angle) condition does not guarantee congruence, as two different triangles can be constructed with the same two sides and a non-included angle. The ASA (Angle Side Angle) and AAS (Angle Angle Side) conditions are also explained as sufficient for congruence. The RHS (Right angle, Hypotenuse, Side) condition is introduced for right-angled triangles: if the hypotenuse and one side are equal, the triangles are congruent. The section concludes with a summary of all sufficient conditions for triangle congruence.
- SSS condition: Triangles with three equal sides are congruent.
- SAS condition: Two sides and the included angle equal imply congruence.
- ASA and AAS conditions: Two angles and a side equal imply congruence.
- SSA condition does not guarantee congruence.
- RHS condition applies to right-angled triangles for congruence.
- Correct vertex correspondence is essential when expressing congruence.
- 📌 SSS (Side Side Side) condition: Three equal sides guarantee triangle congruence.
- 📌 SAS (Side Angle Side) condition: Two sides and included angle equal guarantee congruence.
- 📌 ASA (Angle Side Angle) condition: Two angles and included side equal guarantee congruence.
1.3 Angles of Isosceles and Equilateral Triangles
Concept1.3 Angles of Isosceles and Equilateral Triangles
This section uses congruence to explore properties of isosceles and equilateral triangles. An isosceles triangle has two equal sides. For ΔABC with AB = AC and ∠A = 80°, the altitude AD is constructed perpendicular to BC. Triangles ADB and ADC are ri
Practice Questions — Geometric
Includes NCERT exercise questions with answers
Q1.ΔABC is isosceles with AB = AC, and ∠A = 80°. What can we say about ∠B and ∠C? Construct the altitude from A to BC. Can you use this fact to find ∠B and ∠C?
Answer:
Since ΔABC is isosceles with AB = AC, the angles opposite these sides are equal. Constructing the altitude AD from A to BC creates two right triangles, ΔADB and ΔADC. By RHS congruence (Right angle, Hypotenuse, Side), ΔADB ≅ ΔADC. Therefore, ∠B = ∠C. Since the sum of angles in ΔABC is 180°, we have ∠A + ∠B + ∠C = 180°. Given ∠A = 80°, and ∠B = ∠C, let each be x. Then 80° + x + x = 180°, so 2x = 100°, x = 50°. Hence, ∠B = ∠C = 50°.
Explanation:
1. Given AB = AC, so ΔABC is isosceles. 2. Construct altitude AD perpendicular to BC. 3. Triangles ΔADB and ΔADC have: - AD common side, - AB = AC (given), - ∠ADB = ∠ADC = 90° (by construction). 4. By RHS congruence, ΔADB ≅ ΔADC. 5. Corresponding angles ∠B and ∠C are equal. 6. Sum of angles in ΔABC = 180°, so 80° + ∠B + ∠C = 180°. 7. Since ∠B = ∠C, 80° + 2∠B = 180° ⇒ 2∠B = 100° ⇒ ∠B = 50°. 8. Therefore, ∠B = ∠C = 50°.
Q2.What can we say about the angles of an equilateral triangle? Verify this by construction. What could be their measures?
Answer:
In an equilateral triangle, all sides are equal. Using the fact that angles opposite equal sides are equal, all three angles are equal. Since the sum of angles in a triangle is 180°, each angle measures 180° ÷ 3 = 60°. This can be verified by constructing an equilateral triangle and measuring its angles.
Explanation:
1. Equilateral triangle has AB = BC = CA. 2. Angles opposite equal sides are equal, so ∠A = ∠B = ∠C. 3. Sum of angles in triangle = 180°. 4. Therefore, 3 × ∠A = 180° ⇒ ∠A = 60°. 5. Construction of equilateral triangle and measuring angles confirms this.
Q3.1. ΔAIR ≅ ΔFLY. Identify the corresponding vertices, sides and angles. 2. Each of the following cases contains certain measurements taken from two triangles. Identify the pairs in which the triangles are congruent to each other, with reason. Express the congruence whenever they are congruent. (a) AB = DE, BC = EF, CA = DF (b) AB = EF, ∠A = ∠E, AC = ED (c) AB = DF, ∠B = ∠D = 90°, AC = FE (d) ∠A = ∠D, ∠B = ∠E, AC = DF (e) AB = DF, ∠B = ∠F, AC = DE 3. It is given that OB = OC, and OA = OD. Show that AB is parallel to CD. [Hint: AD is a transversal for these two lines. Are there any equal alternate angles?] 4. ABCD is a square. Show that ΔABC ≅ ΔADC. Is ΔABC also congruent to ΔCDA? Give more examples of two triangles where one triangle is congruent to the other in two different ways, as in the case above. Can you give an example of two triangles where one is congruent to the other in six different ways? 5. Find ∠B and ∠C, if A is the centre of the circle. 6. Find the missing angles. As per the convention that we have been following, all line segments marked with a single ‘|’ are equal to each other and those marked with a double ‘|’ are equal to each other, etc.
Answer:
1. Corresponding vertices: A ↔ F, I ↔ L, R ↔ Y. Corresponding sides: AI ↔ FL, IR ↔ LY, AR ↔ FY. Corresponding angles: ∠A ↔ ∠F, ∠I ↔ ∠L, ∠R ↔ ∠Y. 2. (a) AB=DE, BC=EF, CA=DF → SSS congruence → ΔABC ≅ ΔDEF. (b) AB=EF, ∠A=∠E, AC=ED → SAS congruence → ΔABC ≅ ΔEFD. (c) AB=DF, ∠B=∠D=90°, AC=FE → RHS congruence → ΔABC ≅ ΔDFE. (d) ∠A=∠D, ∠B=∠E, AC=DF → ASA congruence → ΔABC ≅ ΔDEF. (e) AB=DF, ∠B=∠F, AC=DE → Not sufficient for congruence (two angles and non-included side). 3. Given OB=OC and OA=OD, consider transversal AD intersecting lines AB and CD. Since triangles OAB and OCD are congruent (by SSS), alternate interior angles are equal, so AB ∥ CD. 4. ABCD is a square. Triangles ΔABC and ΔADC share side AC, and AB=AD, BC=DC (all sides equal in square). By SAS, ΔABC ≅ ΔADC. Since ΔADC and ΔCDA are the same triangle (just different vertex order), ΔABC is not congruent to ΔCDA as distinct triangles. Examples of triangles congruent in two different ways include isosceles right triangles where congruence can be shown by SAS and RHS. Two triangles congruent in six different ways is not possible as there are only four standard congruence criteria. 5. Since A is the center of the circle, OA=OB=OC (radii). Triangle OBC is isosceles with OB=OC, so ∠B=∠C. Using the properties of circle and triangle sum, find ∠B and ∠C accordingly. 6. Use the markings to identify equal sides and apply properties of triangles (sum of angles = 180°, angles opposite equal sides are equal) to find missing angles step-by-step.
Explanation:
Detailed reasoning for each part: 1. Correspondence is by naming order. 2. Use congruence criteria: - SSS: all three sides equal. - SAS: two sides and included angle equal. - RHS: right angle, hypotenuse, and one side equal. - ASA: two angles and included side equal. 3. Use congruent triangles and alternate interior angles to prove parallelism. 4. Use properties of square and congruence criteria. 5. Use circle radius equality and isosceles triangle properties. 6. Use markings and triangle angle sum to find missing angles.
Q4.Draw lines and split the region consisting of white squares into 6 smaller congruent regions.
Answer:
To split the given region of white squares into 6 smaller congruent regions, draw lines such that each smaller region is congruent in shape and size. This can be done by dividing the figure symmetrically, ensuring equal areas and congruent shapes. The exact lines depend on the figure shown, but typically involve drawing lines parallel or at angles that create equal partitions.
Explanation:
1. Observe the shape and count the white squares. 2. Identify symmetry axes or points. 3. Draw lines dividing the region into 6 parts of equal area and shape. 4. Verify congruence by superimposition or measuring sides and angles.
Q5.What does it mean when two geometric figures are said to be congruent?
Answer:
Congruent figures are those that have the same shape and size. They can be exactly superimposed on each other, meaning one can be placed over the other so that they fit perfectly.
Explanation:
Congruent figures have identical shape and size, which means all corresponding sides and angles are equal. When placed one over the other, they coincide exactly without any gaps or overlaps. For example, two identical triangles or symbols are congruent if they match perfectly after rotation or flipping.
Q6.If two symbols have arm lengths AB = 4 cm and BC = 8 cm, can these measurements alone guarantee that the two symbols are congruent?
Answer:
No, arm lengths alone are not sufficient because the angle between them can vary
Explanation:
Having the same arm lengths AB and BC does not guarantee congruence because the angle ∠ABC can be different, resulting in different shapes. To ensure congruence, the angle between these arms must also be the same.
Q7.Which three measurements are sufficient to recreate the symbol exactly if AB = 4 cm, BC = 8 cm, and the angle between them is 80°?
Answer:
AB, BC, and ∠ABC
Explanation:
The two arm lengths AB and BC along with the included angle ∠ABC fix the shape and size of the figure uniquely, allowing exact reconstruction.
Q8.Two figures are congruent if one can be exactly superimposed on the other. Which of the following transformations can be used before superimposing to check congruence?
Answer:
Rotation or flipping (reflection)
Explanation:
Congruence allows rotation and flipping of figures before superimposing. Scaling or shearing changes size or shape, so they are not allowed for congruence.
All 7 Chapters in Ganita Prakash-II
Mathematics · Class 7