PROPORTIONAL 3 REASONING–2
PROPORTIONAL 3 REASONING–2 — Study Notes
NCERT-aligned · 7 notes · 3 shown free
Introduction
ExplanationIntroduction
The chapter 'Proportional Reasoning – 2' builds upon the foundational concept of proportionality introduced earlier. It focuses on understanding and applying the idea of ratios and proportions in various contexts, particularly in solving problems involving direct and inverse proportions. This chapter aims to develop the ability to reason quantitatively and to solve real-life problems by recognizing proportional relationships between quantities. The concept of proportionality is central to many areas of mathematics and science, as it helps in comparing quantities and understanding how one quantity changes in relation to another. The chapter begins by revisiting the concept of ratios and proportions, then extends to more complex applications such as unitary method, percentage, and problems involving direct and inverse proportions. Through examples and activities, students learn to identify proportional relationships and apply appropriate methods to solve problems efficiently. The chapter also emphasizes the importance of proportional reasoning in everyday life, such as in calculating prices, speed, time, and work. By the end of this chapter, students will be able to solve problems involving proportional quantities with confidence and understand the underlying mathematical principles.
- Proportional reasoning involves understanding the relationship between two or more quantities.
- Ratios compare two quantities of the same kind by division.
- Proportions state that two ratios are equal.
- Direct proportion means when one quantity increases, the other increases at the same rate.
- Inverse proportion means when one quantity increases, the other decreases at the same rate.
- Unitary method is a technique to find the value of one unit and then find the value for any number of units.
- 📌 Ratio: A comparison of two quantities of the same kind by division.
- 📌 Proportion: An equation stating that two ratios are equal.
- 📌 Direct Proportion: A relationship where two quantities increase or decrease together at the same rate.
Direct Proportion
ExplanationDirect Proportion
Direct proportion is a fundamental concept where two quantities increase or decrease in such a way that their ratio remains constant. If one quantity doubles, the other also doubles; if one is halved, the other is halved as well. Mathematically, two quantities a and b are said to be in direct proportion if a/b = k, where k is a constant. This means that a = k × b. The constant k is called the constant of proportionality. Problems involving direct proportion are common in daily life such as calculating the cost of items, speed and distance, time and work, etc. To solve direct proportion problems, we often use the unitary method where the value of one unit is found first and then multiplied to find the value for the required number of units. Another method is to use the property of proportion: if a/b = c/d, then a × d = b × c. This cross-multiplication helps in solving for unknown quantities. The section includes several examples demonstrating how to identify direct proportion and solve related problems. For instance, if 4 pens cost ₹20, then 1 pen costs ₹20 ÷ 4 = ₹5, so 7 pens cost 7 × ₹5 = ₹35. The section also explains how to handle problems involving speed, distance, and time, where speed is directly proportional to distance when time is constant. Understanding direct proportion is crucial for developing problem-solving skills and applying mathematical reasoning to real-world situations.
- Two quantities are in direct proportion if their ratio is constant.
- If a/b = k, then a = k × b where k is the constant of proportionality.
- Cross multiplication is used to solve proportion problems: a/b = c/d ⇒ a × d = b × c.
- Unitary method helps find the value of one unit to solve problems.
- Direct proportion applies to cost, speed-distance-time, and work problems.
- Graph of direct proportion is a straight line passing through the origin.
- 📌 Constant of Proportionality: The constant ratio between two quantities in direct proportion.
- 📌 Cross Multiplication: A method to solve proportions by multiplying diagonally.
- 📌 Unitary Method: Finding the value of one unit to solve for multiple units.
Inverse Proportion
ExplanationInverse Proportion
Inverse proportion describes a relationship between two quantities where one quantity increases as the other decreases in such a way that their product remains constant. If one quantity doubles, the other halves. Mathematically, two quantities a and
Practice Questions — PROPORTIONAL 3 REASONING–2
Includes NCERT exercise questions with answers
Q1.1. Which of the following pairs of quantities are in inverse proportion? (i) The number of taps filling a water tank and the time taken to fill it. (ii) The number of painters hired and the days needed to paint a wall of fixed size. (iii) The distance a car can travel and the amount of petrol in the tank. (iv) The speed of a cyclist and the time taken to cover a fixed route. (v) The length of cloth bought and the price paid at a fixed rate per metre. (vi) The number of pages in a book and the time required to read it at a fixed reading speed.
Answer:
Answer: (i) Inverse proportion: More taps → less time to fill the tank. (ii) Inverse proportion: More painters → fewer days to paint. (iii) Direct proportion: More petrol → more distance. (iv) Inverse proportion: Higher speed → less time. (v) Direct proportion: More cloth → more price. (vi) Direct proportion: More pages → more time to read.
Explanation:
Inverse proportion means when one quantity increases, the other decreases such that their product is constant. Direct proportion means both quantities increase or decrease together maintaining a constant ratio.
Q2.2. If 24 pencils cost ₹120, how much will 20 such pencils cost?
Answer:
Solution: Cost of 24 pencils = ₹120 Cost of 1 pencil = 120 ÷ 24 = ₹5 Cost of 20 pencils = 20 × 5 = ₹100
Explanation:
Since cost is directly proportional to number of pencils, unit cost is found first and multiplied by required quantity.
Q3.3. A tank on a building has enough water to supply 20 families living there for 6 days. If 10 more families move in there, how long will the water last? What assumptions do you need to make to work out this problem?
Answer:
Solution: Number of families initially = 20 Water lasts = 6 days New number of families = 20 + 10 = 30 Since more families → less days, quantities are inversely proportional. Let x = new number of days water will last. 20 × 6 = 30 × x 120 = 30x x = 120 ÷ 30 = 4 days Assumptions: Each family uses water at the same rate.
Explanation:
Inverse proportion applies because more families consume water faster, reducing days water lasts.
Q4.4. Fill in the average number of hours each living being sleeps in a day by looking at the charts. Select the appropriate hours from this list : 15, 2.5, 20, 8, 3.5, 13, 10.5, 18.
Answer:
Answer depends on the charts provided in the textbook (not included here). Students should match each living being with the appropriate sleep hours from the given list.
Explanation:
This question requires observation of charts to fill in correct average sleep hours.
Q5.5. The pie chart on the right shows the result of a survey carried out to find the modes of transport used by children to go to school. Study the pie chart and answer the following questions. (i) What is the most common mode of transport? (ii) What fraction of children travel by car? (iii) If 18 children travel by car, how many children took part in the survey? How many children use taxis to travel to school? (iv) By which two modes of transport are equal numbers of children travelling?
Answer:
Answer: (i) Most common mode is Bus (largest sector 120°). (ii) Fraction traveling by car = 60°/360° = 1/6. (iii) If 18 children travel by car (1/6), total children = 18 × 6 = 108. Taxis sector = 60°, so number using taxis = (60/360) × 108 = 18. (iv) Two modes with equal numbers are Cycle and Taxi (both 60° sectors).
Explanation:
Use angle measures of pie chart sectors to find fractions and numbers of children for each mode.
Q6.6. Three workers can paint a fence in 4 days. If one more worker joins the team, how many days will it take them to finish the work? What are the assumptions you need to make?
Answer:
Solution: Work done by 3 workers in 4 days = 1 fence Work done by 1 worker in 1 day = 1/(3×4) = 1/12 fence With 4 workers, work done in 1 day = 4 × 1/12 = 1/3 fence Days to finish = 1 ÷ (1/3) = 3 days Assumptions: All workers work at the same rate and work independently.
Explanation:
More workers reduce the number of days needed, inverse proportion applies.
Q7.7. It takes 6 hours to fill 2 tanks of the same size with a pump. How long will it take to fill 5 such tanks with the same pump?
Answer:
Solution: Time to fill 2 tanks = 6 hours Time to fill 1 tank = 6 ÷ 2 = 3 hours Time to fill 5 tanks = 5 × 3 = 15 hours
Explanation:
Time is directly proportional to number of tanks filled.
Q8.8. A given set of chairs are arranged in 25 rows, with 12 chairs in each row. If the chairs are rearranged with 20 chairs in each row, how many rows does this new arrangement have?
Answer:
Solution: Total chairs = 25 × 12 = 300 New arrangement: 20 chairs per row Number of rows = 300 ÷ 20 = 15 rows
Explanation:
Total number of chairs remains the same; rearranging changes rows and columns inversely.
All 7 Chapters in Ganita Prakash Part-II
Mathematics · Class 8