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Arithmetic Progressions

🎓 Class 10📖 Mathematics📖 5 notes🧠 15 Q&A⏱️ ~8 min

Arithmetic ProgressionsStudy Notes

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5.1 Introduction

Explanation

5.1 Introduction

This introductory section highlights the presence of patterns in nature and everyday life, which often follow specific sequences or progressions. It begins by pointing out natural examples such as the petals of a sunflower, the holes in a honeycomb, grains on a maize cob, and spirals on pineapples and pine cones, all exhibiting regular patterns. The section then transitions to patterns observed in daily life, emphasizing that many sequences of numbers or measurements follow a certain rule or pattern. Several examples are provided to illustrate this concept: (i) Reena's salary progression: She starts with a monthly salary of ₹8000 and receives an annual increment of ₹500. Her salary over the years forms the sequence 8000, 8500, 9000, ... (ii) Ladder rung lengths: The lengths decrease uniformly by 2 cm from bottom to top, starting with 45 cm at the bottom rung. The lengths are 45, 43, 41, 39, 37, 35, 33, 31 cm. (iii) Savings scheme: An investment of ₹8000 grows by a factor of 5/4 every 3 years, resulting in maturity amounts of 10000, 12500, 15625, 19531.25 after 3, 6, 9, and 12 years respectively. (iv) Number of unit squares in squares of side 1, 2, 3, ... units, which are 1², 2², 3², ... (v) Shakila's daughter’s money box: Starting with ₹100 on the first birthday and increasing by ₹50 each year, the amounts are 100, 150, 200, 250, ... (vi) Rabbit pairs reproduction: Starting with one pair, the number of pairs over months follows the sequence 1, 1, 2, 3, 5, 8, ... The section concludes by noting that these examples show different types of patterns: some involve adding a fixed number (arithmetic progression), some involve multiplication, and others involve squares or Fibonacci-type sequences. The chapter will focus on the pattern where succeeding terms are obtained by adding a fixed number to the preceding term, known as Arithmetic Progressions (AP). It will cover how to find the nth term and the sum of n terms of such sequences and apply these concepts to solve real-life problems. **Table on page 13 (6×5)** | | a | d | n | an | | --- | --- | --- | --- | --- | | (i) | 7 | 3 | 8 | ... | | (ii) | -18 | ... | 10 | 0 | | (iii) | ... | -3 | 18 | -5 | | (iv) | -18.9 | 2.5 | ... | 3.6 | | (v) | 3.5 | 0 | 105 | ... |

  • Patterns exist in nature and daily life, often following specific sequences.
  • Examples include salary increments, ladder rung lengths, savings growth, and biological reproduction.
  • Some sequences involve adding a fixed number; others involve multiplication or squares.
  • Arithmetic Progression (AP) is a sequence where each term is obtained by adding a fixed number to the previous term.
  • The chapter focuses on understanding APs, finding nth terms, and sums of terms.
  • Real-life applications of APs will be explored.
  • 📌 Arithmetic Progression (AP): A sequence where each term after the first is obtained by adding a fixed number to the preceding term.
  • 📌 Common difference: The fixed number added to each term to get the next term in an AP.

5.2 Arithmetic Progressions

Definition

5.2 Arithmetic Progressions

This section formally introduces Arithmetic Progressions (APs) by examining several lists of numbers and identifying the pattern of a fixed difference between consecutive terms. It begins with examples: (i) 1, 2, 3, 4, ... (ii) 100, 70, 40, 10, ... (iii) -3, -2, -1, 0, ... (iv) 3, 3, 3, 3, ... (v) -1.0, -1.5, -2.0, -2.5, ... Each term in these sequences is called a term. The section asks how to find the next term in each list and observes the pattern or rule. It notes that in each list, the next term is obtained by adding a fixed number to the previous term: +1, -30, +1, 0, and -0.5 respectively. Such sequences where the difference between consecutive terms is constant are called Arithmetic Progressions (AP). The fixed number added is called the common difference (d), which can be positive, negative, or zero. Notation is introduced: the first term is a1, second term a2, nth term an, and common difference d. The defining property is a2 - a1 = a3 - a2 = ... = an - a(n-1) = d. More examples of APs are given: (a) Heights of students: 147, 148, 149, ..., 157 (b) Minimum temperatures: -3.1, -3.0, -2.9, ..., -2.5 (c) Loan balance after paying 5% monthly: 950, 900, 850, ..., 50 (d) Cash prizes for toppers: 200, 250, 300, ..., 750 (e) Monthly savings: 50, 100, 150, ..., 500 The general form of an AP is expressed as a, a + d, a + 2d, a + 3d, ..., where a is the first term and d the common difference. The section distinguishes between finite APs (with a last term) and infinite APs (without a last term). It emphasizes that to define an AP, both the first term and common difference must be known. Examples with various values of a and d are provided to illustrate positive, negative, zero, fractional, and decimal common differences. The section also explains how to verify if a given list is an AP by checking if the difference between consecutive terms is constant. It stresses that the difference is found by subtracting the kth term from the (k+1)th term. Examples demonstrate this verification process and identify sequences that are not APs, such as the Fibonacci sequence and sequences with irregular differences. Overall, this section lays the foundation for understanding and identifying Arithmetic Progressions.

  • An AP is a sequence where each term after the first is obtained by adding a fixed number (common difference) to the previous term.
  • The common difference d can be positive, negative, or zero.
  • Notation: first term a1 = a, nth term an, common difference d.
  • General form of AP: a, a + d, a + 2d, a + 3d, ...
  • Finite APs have a last term; infinite APs do not.
  • To verify an AP, check if differences between consecutive terms are equal.
  • 📌 Arithmetic Progression (AP): Sequence with constant difference between consecutive terms.
  • 📌 Common difference (d): Fixed number added to each term to get the next.
  • 📌 Finite AP: AP with a last term.

5.3 nth Term of an AP

Explanation

5.3 nth Term of an AP

This section explains how to find the nth term of an Arithmetic Progression (AP) efficiently, using the example of Reena's salary increment introduced earlier. Reena starts with a salary of ₹8000 and receives an annual increment of ₹500. Calculation

Practice QuestionsArithmetic Progressions

Includes NCERT exercise questions with answers

Q1.Which of the following is a finite A.P? (i) 90,80,70,60, … (ii) a, a ─ 2, a ─ 3, a ─ 4 (iii) 3,5,7,9,11,13
A.All
B.(ii) and (iii)
C.Only (iii)
D.(i) and (iii)

Answer:

Only (iii)

Explanation:

[{"id": "ca5ab071-aed0-40fc-84c3-9cf1008eaaf1", "type": "html", "value": " (i) 90, 80, 70, 60 … a₂ ─ a₁ = 80 ─ 90 = ─ 10 a₃ ─ a₂ = 70 ─ 80 = ─ 10 a₄ ─ a₃ = 60 ─ 70 = ─ 10 This is an A.P. but it is an infinite A.P. as we don't know the last term of the A.P. as indicated by the ellipsis. (ii) a, a ─ 2, a ─ 3, a ─ 4 a₂ ─ a₁ = ─ 2 a₃ ─ a₂ = ─ 1 a₄ ─ a₃ = ─ 1 Since a₂ ─ a₁ ≠ a₃ ─ a₂, this is not an A. P. (iii) 3,5,7,9,11,13 a₂ ─ a₁ = 2 a₃ ─ a₂ = 2 a₄ ─ a₃ = 2 Since the common difference is 2, this is an A.P. and it is a Finite A.P. as the last term is given as 13. So the correct option is Option 3 "}]

MediumNCERT
Q2.Determine the First term (a) and the common difference (d) of the A.P. given below: ─ 5, ─ 5, ─ 5, ─ 5, ─ 5, ...
A.a = ─ 5 d = 5
B.a = ─ 5 d = 0
C.a = 5 d = 5
D.a = ─ 5 d = ─ 5

Answer:

a = ─ 5 d = 0

Explanation:

[{"id": "26c5cfe4-4712-4a5f-93f4-206800a44049", "type": "html", "value": " ─ 5, ─5, ─ 5 ,─ 5 … a₂ ─ a₁ = ─ 5 ─ (─ 5) = 0 a₃ ─ a₂ = ─ 5 ─ (─ 5) = 0 a₄ ─ a₃ = ─ 5 ─ (─ 5) = 0 So this is an A.P. with common difference 0 and a = ─ 5 so the correct option is Option 2 "}]

MediumNCERT
Q3.A farmer borrows Rs 10,000 from a friend and promises to pay back 10% of the balance every month. Make a list of the money he repays every month and state which of the following statements are true?
A.It is an A.P. with common difference of ─ 1000 Rs.
B.It is an A.P. with common difference of ─ 100 Rs.
C.It is an A.P. with common difference of 1000 Rs.
D.It is not an A.P.

Answer:

It is not an A.P.

Explanation:

[{"id": "dc46a3ce-1ad0-4f38-b436-519576f83e0c", "type": "html", "value": " Sum borrowed = Rs. 10000 Amount paid back in first month = 10% of Rs. 10000 = Rs. 1000 Balance = Rs. 9000 Amount paid back in second month = 10% of Rs. 9000 = Rs. 900 Balance = Rs. 8100 Amount paid back in third month = 10% of Rs. 8100 = Rs. 810 Balance = Rs 7290 Amount paid back in fourth month = 10% of Rs. 7290 = Rs. 729 List of numbers (money paid back every month) is 1000, 900, 810, 729, ... a₂ ─ a₁ = 900 ─ (1000) = ─ 100 a₃ ─ a₂ = 810 ─ (900) = ─ 90 a₄ ─ a₃ = 729 ─ (810) = ─ 81 Since a₃ ─ a₂ ≠ a₄ ─ a₃, this is not an A.P. so the correct option is Option 4 "}]

MediumNCERT
Q4.The first four terms of an AP, whose first term is –6 and the common difference is 6, are
A.─6, 0, 6, 12
B.─6, ─12, ─18, ─24
C.─6, 0, 6, ─12
D.─6, ─12, ─24, ─48

Answer:

─6, 0, 6, 12

Explanation:

[{"id": "3a9891da-fd90-46bc-9bfa-a4c0b4ce68dd", "type": "html", "value": " In the given A.P., a = ─ 6, d = 6 First term = a = ─ 6 Second term = a + d = ─ 6 + 6 = 0 Third term = a + 2d = ─ 6 + 12 = 6 Fourth term = a + 3d = ─ 6 + 18 = 12 So the correct option is Option 1 "}]

MediumNCERT
Q5.The list of numbers -12, -9, -6, -3, 0, __ _ _ _
A.No an AP
B.An AP with d=3
C.An AP with d=-3
D.An AP with d=0

Answer:

An AP with d=3

MediumNCERT
Q6.Which of the following is NOT an A.P? (i) a, a+1, a+2, a+3 … (ii) 4, 9, 14, 19 (iii) 4, 5, 4, 4, 5, 4, 4, 5 ...
A.All
B.(ii) and (iii)
C.Only (iii)
D.(i) and (iii)

Answer:

Only (iii)

Explanation:

[{"id": "ce521375-bf39-463b-8100-34e000093508", "type": "html", "value": " (i) a, a+1, a+2, a+3 … a₂ ─ a₁ = 1 a₃ ─ a₂ = 1 a₄ ─ a₃ = 1 So, this is an A.P. (ii) 4, 9, 14, 19 a₂ ─ a₁ = 5 a₃ ─ a₂ = 5 a₄ ─ a₃ = 5 So, this is an A. P. (iii) 4, 5, 4, 4, 5, 4, 4, 5…. a₂ ─ a₁ = 1 a₃ ─ a₂ = ─ 1 a₄ ─ a₃ = 0 Since a₃ ─ a₂ ≠ a₄ ─ a₃, this is not an A.P. Hence, the correct option is Option 3 "}]

MediumNCERT
Q7.Find the fourth term from the end of the A.P.: 2, 5, 8, …, 35.
A.26
B.12
C.29
D.23

Answer:

26

Explanation:

[{"id": "a07768c1-4d5e-4490-9cc3-aa0b9994d3de", "type": "html", "value": " A.P. is 2, 5, 8, ..., 35 a = 2, d = 3 , l = 35 an = a + (n ─ 1) d 35 = 2 + (n ─ 1) 3 33 = 3n ─ 3 36 = 3n n = 12 So the A.P. has 12 terms. Fourth term from the end will be 9th term. a₉ = 2 + (9 ─ 1)3 a₉ = 2 + 24 = 26 So the correct answer is option1 "}]

MediumNCERT
Q8.In a children's balloon race, a bucket is placed at the starting point, which is 2m away from the first balloon and the other balloons are placed 3m apart in a straight line.There are 12 balloons in the line. A child starts from the bucket, picks up the nearest balloon, runs back with it, drops it in the bucket, runs back to pick up the next balloon and the again runs back to drop it in the bucket. The child continues the same way till all the balloons are in the bucket. Find the total distance run by the child.
A.222 m
B.444 m
C.666 m
D.888 m

Answer:

444 m

Explanation:

[{"id": "5b05bdc0-0e8c-4651-ab89-ce5e50fa12e6", "type": "html", "value": " Distance of nearest balloon from the starting point = 2m Number of balloons = 12 The distance of the balloons are: 2, 5, 8, 11 ….. These numbers form an AP with a = 2 and d = 3 We know, S₁₂ = 12/2 [2 x 2 + (12 ─ 1)3] S₁₂ = 6 ( 4 + 11 x 3) = 6(37) = 222 As everytime the child has to run back to the bucket therefore the total distance that the child has to run will be 2 times of S₁₂ So,the total distance that the child runs = 2 x 222 m = 444 m So the correct option is Option 2 "}]

MediumNCERT