Areas Related to Circles
Areas Related to Circles — Study Notes
NCERT-aligned · 6 notes · 3 shown free
11.1 Areas of Sector and Segment of a Circle
Explanation11.1 Areas of Sector and Segment of a Circle
In this section, we revisit and deepen our understanding of two important parts of a circle: the sector and the segment. A sector of a circle is the region enclosed by two radii and the arc between them, essentially a 'slice' of the circle. The angle formed at the center of the circle by these two radii is called the angle of the sector. For example, if the circle's center is O and the radii are OA and OB, then the sector is the region OAPB, and the angle ∠AOB is the sector's angle. There are two sectors formed by any two radii: the minor sector (smaller area) and the major sector (larger area). The major sector's angle is 360° minus the minor sector's angle. A segment of a circle is the region bounded by a chord and the corresponding arc. If AB is a chord, then the segment is the region APB enclosed between the chord AB and the arc APB. Similar to sectors, there are minor and major segments formed by the chord. Understanding these parts of a circle is crucial because they appear frequently in geometry problems and real-world applications such as designing circular fields, wheels, and arcs in architecture. The section sets the stage for deriving formulas to calculate the areas of these sectors and segments, which are essential for solving practical problems involving parts of circles.
- Sector is the region enclosed by two radii and the arc between them.
- Segment is the region enclosed by a chord and the corresponding arc.
- Each pair of radii or chord divides the circle into minor and major sectors or segments.
- The angle of the sector is the angle formed at the center by the two radii.
- Minor sector/segment refers to the smaller part, major sector/segment to the larger part.
- Understanding sectors and segments is foundational for calculating areas related to circles.
- 📌 Sector: Part of a circle enclosed by two radii and the arc between them.
- 📌 Segment: Part of a circle enclosed by a chord and the corresponding arc.
- 📌 Minor sector/segment: Smaller part formed by radii or chord.
Deriving the Formula for Area of a Sector and Length of an Arc
ExplanationDeriving the Formula for Area of a Sector and Length of an Arc
This section focuses on finding formulas to calculate the area of a sector and the length of the arc corresponding to that sector. Consider a circle with center O and radius r. Let the sector be formed by two radii OA and OB enclosing an angle θ degrees at the center (see Fig. 11.3). We know the area of the entire circle is πr², which corresponds to a central angle of 360°. Using the unitary method, the area corresponding to 1° is (πr²)/360. Therefore, the area of the sector with angle θ is (θ/360) × πr². This formula allows us to calculate the area of any sector by knowing the radius and the angle it subtends at the center. Similarly, the length of the entire circumference is 2πr, corresponding to 360°. The length of the arc corresponding to angle θ is (θ/360) × 2πr. This formula helps us find the length of any arc when the radius and central angle are known. These formulas are fundamental in geometry and have practical applications in fields such as engineering, architecture, and design, where parts of circles are common.
- Area of full circle = πr² corresponds to 360° angle.
- Area of sector with angle θ = (θ/360) × πr².
- Circumference of circle = 2πr corresponds to 360° angle.
- Length of arc with angle θ = (θ/360) × 2πr.
- Unitary method is used to derive these formulas.
- These formulas are essential for calculating areas and lengths related to parts of circles.
- 📌 Radius (r): Distance from center to any point on the circle.
- 📌 Central angle (θ): Angle subtended at the center by two radii.
- 📌 Arc length: Distance along the curved line of the sector.
Area of a Segment of a Circle
ExplanationArea of a Segment of a Circle
A segment of a circle is the region bounded by a chord and the corresponding arc. To find the area of a segment, we use the relationship between the area of the sector formed by the two radii and the chord, and the area of the triangle formed by the
Practice Questions — Areas Related to Circles
Includes NCERT exercise questions with answers
Q1.Area of a sector of angle 150° of a circle with radius 21 cm is _____. (Take π = 22/7)
Answer:
577.5 cm²
Explanation:
[{"id": "66abb405-80aa-4dab-94f5-1d06d6a69374", "type": "html", "value": " We know that the Area of a sector of a circle = θ/360 πr² Given, θ = 150⁰ , r = 21 cm So, Area of sector = 150/ 360 π(21)² = 1155/2 = 577.5 cm² Hence the correct answer is option 1. "}]
Q2.The radius of a circle is 10 cm. If the area of a sector of the circle is 100 cm², then the area of its corresponding major sector is ____________. (Take π = 3.14)
Answer:
214 cm²
Explanation:
[{"id": "d03ff9a3-c750-442d-a3ed-2161991604c0", "type": "html", "value": " Given : radius of circle = 10 cm Area of minor sector = θ/360 πr² = 100 cm² Area of circle = π r² = 100π Area of Major sector = π r² ─ θ/360 πr² = 100π ─ 100 = 100(3.14) ─ 100 = 314 ─ 100 = 214 cm² Hence the correct answer is option 2 "}]
Q3.A sector is cut off from a circle of radius 21 cm. The angle of the sector is 120⁰. The area of the remaining part of the circle is _______.
Answer:
924 cm²
Explanation:
[{"id": "2f03840f-6e5d-45d4-b5c6-b96d0b7fc89f", "type": "html", "value": " Area of circle = π r² = 22/7 × 21 × 21 = 1386 cm² Area of sector = θ/360 π r² = 120/360 × 1386 cm² = 1/3 × 1386 = 462 cm² So, Area of Remaining portion = Area of Circle ─ Area of sector = 1386 cm² ─ 462 cm² = 924 cm² Hence the correct answer is option 3. "}]
Q4.A circular disc of radius 6 cm is divided into three sectors with the angles of sectors measuring 170⁰, 100⁰ and 90⁰, respectively. The ratio of the areas of these sectors is ________.
Answer:
17:10:09
Explanation:
[{"id": "6da75065-3ed4-409d-8c71-a8122c5d3235", "type": "html", "value": " Given : Circular disc is divided into 3 sectors. θ₁ = 170⁰, θ₂= 100⁰, θ₃ = 90⁰ , r = 6 cm Area of minor sector = θ/360 πr² Area of sector 1 = 170/360 × 36 π Area of sector 2 = 100/360 ×36 π Area of sector 3 = 90/360 × 36 π Hence, Ratio of areas of sectors = 170:100:90 = 17:10:9 Hence the correct answer is option 4. "}]
Q5.The length of the minute hand of a clock is 14 cm. The area swept by the minute hand between 7:00PM to 7:40PM is _______.
Answer:
410.67 cm²
Explanation:
[{"id": "e75f9b81-bafc-4310-bb77-2face185ffa3", "type": "html", "value": " Radius of minute hand = 14 cm Angle described by minute hand in 1 minute = 6⁰ Between 7.00 pm to 7.40 pm , there are 40 minutes. Angle described by minute hand in 40 minutes = 40 × 6⁰ = 240⁰ We know, Area of a sector = θ/360 πr² Area of sector = 240/360 × 22/7 × 14² = 410.67 cm² Hence the correct answer is option 2. "}]
Q6.A segment of a circle is bounded by which of the following?
Answer:
A chord and an arc
Explanation:
[{"id": "831a2fdb-6bd2-4fe2-b4f0-8259866d32de", "type": "html", "value": " We know that the the portion (or part) of the circular region enclosed between a chord and the corresponding arc is called a segment of the circle. Hence the correct answer is option 1. "}]
Q7.A chord of a circle of radius 50 cm subtends an angle of 120° at the centre. The area of the corresponding segment of the circle is ________. (Take π = 3.14 , √3 = 1.73)
Answer:
1,535.5 cm²
Explanation:
[{"id": "e6e2ac50-6913-4ac8-adaf-fa5e728a30e5", "type": "html", "value": " Given : r = 50 cm , θ = 120⁰ Area of segment = r²[ θ/360π ─ sinθ/2 cosθ/2] Area = 50² [ 120 × π/360 ─√3/2 × 1/2] = 2500 { 3.14/3 ─1.73/4] =2500 . 0.6142 = 1,535.5 cm² Hence the correct answer is Option 2. "}]
Q8.A chord of a circle of radius 20 cm subtends an angle of 60° at the centre. The area of the corresponding major segment of the circle is _________. (Use π = 3.14).
Answer:
1,219.68 cm²
Explanation:
[{"id": "9b123384-a268-454c-91df-7724efb4ae21", "type": "html", "value": " Given : r = 20 cm , θ = 60⁰ Area of minor segment = r²[ θ/360π ─ sinθ/2 cosθ/2] Area of minor segment = 20² [ 60 × π/360 ─ 1/2 × √3/2 ] = 400 (3.14/6 ─1.73/4) = 400 × (0.5233 ─ 0.4325) = 36.32 cm² Area of circle = π r² = 400π = 1256 cm² Area of major segment = Area of circle ─ Area of minor segment Area of major segment = 1256 ─ 36.32 = 1219.68 cm² Hence the correct answer is option 3. "}]
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