Alternating Current
Alternating Current — Study Notes
NCERT-aligned · 9 notes · 3 shown free
7.1 INTRODUCTION
Explanation7.1 INTRODUCTION
This section introduces the fundamental concept of alternating current (AC) as distinct from direct current (DC). Direct current flows in a constant direction with a steady magnitude, whereas alternating current and voltage vary sinusoidally with time. The common electrical mains supply in homes and offices is an alternating voltage that varies like a sine function over time. The current driven by such a voltage is called alternating current (AC current). AC is preferred over DC for power transmission and distribution because AC voltages can be easily transformed from one voltage level to another using transformers, enabling economical transmission over long distances. AC circuits also exhibit unique characteristics exploited in many devices, such as radio tuning, where the frequency-selective properties of AC circuits are utilized. The section also notes the linguistic redundancy in the terms 'AC voltage' and 'AC current' but acknowledges their universal acceptance. The importance of AC in modern electrical energy systems is emphasized, setting the stage for detailed study of AC circuit behavior in subsequent sections.
- Direct current (DC) flows in one direction with constant magnitude.
- Alternating current (AC) voltage and current vary sinusoidally with time.
- Most electrical energy is transmitted and distributed as AC.
- AC voltages can be efficiently transformed to different voltage levels using transformers.
- AC circuits have special properties used in devices like radios.
- Terminology 'AC voltage' and 'AC current' are widely accepted despite redundancy.
- 📌 Alternating Current (AC): Current that reverses direction periodically and varies sinusoidally with time.
- 📌 Direct Current (DC): Current that flows in one direction with constant magnitude.
- 📌 AC Voltage: Voltage that varies sinusoidally with time.
7.2 AC VOLTAGE APPLIED TO A RESISTOR
Explanation7.2 AC VOLTAGE APPLIED TO A RESISTOR
This section studies the response of a pure resistor connected to an AC voltage source producing sinusoidally varying voltage v = v_m sin ωt, where v_m is the peak voltage and ω is the angular frequency. Applying Kirchhoff's loop rule to the circuit, the instantaneous current i through the resistor of resistance R is found to be i = (v_m / R) sin ωt = i_m sin ωt, where i_m is the peak current amplitude. This obeys Ohm's law for AC circuits. The voltage and current are in phase, meaning their maxima, minima, and zero crossings occur simultaneously. The current varies sinusoidally with positive and negative values, so the average current over a cycle is zero. However, power dissipation is not zero because power depends on i², which is always positive. The instantaneous power dissipated is p = i² R = i_m² R sin² ωt. The average power over one cycle is (1/2) i_m² R, derived using the trigonometric identity for sin² ωt. To express power in a form analogous to DC circuits, root mean square (rms) or effective values of current and voltage are introduced: I = i_m / √2 and V = v_m / √2. The average power then becomes P = I² R = V I, similar to DC power formulas. The section includes a solved example calculating resistance, peak voltage, and rms current for a light bulb rated at 100 W on a 220 V supply.
- AC voltage applied to resistor: v = v_m sin ωt.
- Current through resistor: i = i_m sin ωt, with i_m = v_m / R.
- Voltage and current are in phase in a pure resistor.
- Instantaneous power: p = i² R = i_m² R sin² ωt.
- Average power over a cycle: P = (1/2) i_m² R.
- Root mean square (rms) values defined as I = i_m / √2 and V = v_m / √2.
- Power expressed as P = I² R = V I, analogous to DC power.
- 📌 Root Mean Square (rms) Current: The effective value of AC current producing the same heating effect as DC current.
- 📌 Ohm's Law for AC: i = v / R applies for resistors with AC voltage.
- 📌 Instantaneous Power: Power at any instant, p = i² R for resistors.
7.3 REPRESENTATION OF AC CURRENT AND VOLTAGE BY ROTATING VECTORS — PHASORS
Explanation7.3 REPRESENTATION OF AC CURRENT AND VOLTAGE BY ROTATING VECTORS — PHASORS
This section introduces phasors as a powerful tool to analyze AC circuits, especially to represent the phase relationships between voltage and current. A phasor is a rotating vector in the complex plane that rotates with angular velocity ω. The verti
Practice Questions — Alternating Current
Includes NCERT exercise questions with answers
Q1.The primary and secondary coils of a transformer have 50 and 1500 turns respectively. The magnetic flux linked with the primary coil is given by Φ = Φ ο + 4 t, where Φ ο is a constant. The output voltage across the secondary coil is
Answer:
120 V
Explanation:
[{"id": "d695ad3d-664f-0694-2928-9365a577eeec", "type": "html", "value": " E p = d Φ/ dt = 4V E s = N s x E p / N p = 1500 x 4 / 50 = 120 V "}]
Q2.In an ideal LC- circuit, the capacitor is charged by connecting it to a d.c source, which is then disconnected. The current in the circuit
Answer:
oscillates instantaneously
Q3.A fully charged capacitor C with initial charge q o , is connected to a coil of self inductance L at t = 0. The time at which, the energy is stored equally, between the electric and magnetic fields is
Answer:
(π / 4) (LC) 1/2
Q4.The power factor of an a.c circuit having resistance R and inductance L (connected in series) is
Answer:
R / ( R 2 + ω 2 L 2 ) 1/2
Q5.In a series LCR – circuit, resistance, voltage and frequency of the main supply is 200 Ω, 220 V and 50 Hz respectively. If capacitor is taken out from the circuit, the current lags behind the voltage by 30 o . If inductor is taken out from the circuit, the current leads the voltage by 30 o . The power dissipated in the LCR- circuit is
Answer:
242 W
Explanation:
[{"id": "abc81be5-9abe-b825-4e5c-2866165a41f0", "type": "html", "value": " When capacitance is taken out, the circuit is LR tanΦ = ωL / R ωL = 200 / √3 "}]
Q6.A series LCR circuit with C = 10μF and ω = 1000 rad/s, has maximum current flowing through it. The value of inductance will be
Answer:
100 mH
Explanation:
[{"id": "4d87ca9b-21fd-bc2a-102b-5578241bcc1d", "type": "html", "value": " The current is maximum at resonance X C = X L 1 / ωC = ωL L = 1/ ω 2 C = 1 / 1000 2 x 10 x 10 -6 =100mH "}]
Q7.A capacitor
Answer:
blocks d.c but provides an easy path for a.c
Q8.The reactance of a capacitor of capacitance C, is X. If both the frequency and capacitance are doubled, the new reactance will be
Answer:
X/4
All 8 Chapters in Physics Part-I
Physics · Class 12